Answer:
0.5 < t < 2
Step-by-step explanation:
The function reaches its maximum height at ...
t = -b/(2a) = -16/(2(-16)) = 1/2 . . . . . . where a=-16, b=16, c=32 are the coefficients of f(t)
The function can be factored to find the zeros.
f(t) = -16(t^2 -1 -2) = -16(t -2)(t +1)
The factors are zero for ...
x = -1 and x = +2
The ball is falling from its maximum height during the period (0.5, 2), so that is a reasonable domain if you're only interested in the period when the ball is falling.
