Ask question

Ask question

All categories

3 years ago

5

Simplify the fraction 12/20

2 answers:

katovenus [111]3 years ago

6 0

The answer to your question is,

3/5. Take the fraction and find the most common number to divide both numbers by. The number to divide it by is 4, which is the highest number you can get to.

-Mabel <3

zysi [14]3 years ago

3 0

The answer is going to be 3/5

You might be interested in

In the table, Pattern A uses the rule "add 3" and Pattern B uses the rule "add 9."

Paladinen [302]

Statement 1 is true.
-Hope this helps, have a nice day! :)

6 0

2 years ago

Solve this pleaseeeee

Ivan

Answer:

-4 < n ≤ 5

Step-by-step explanation:

________________

7 0

2 years ago

M angle 3= 31°. Find m angle 4 (complementary angle)

solniwko [45]

Hi, there.

________

$\boxed{\begin{minipage}{8cm} Complementary angles \\ Complementary angles are angles whose sum \\ is 90^\circ. \text{Using this info, let's consider this:} \\ \text{If an angle's measure is 31 degrees, what's} \\ \text{its \ complement?}\end{minipage}}$

$\text{Set up an equation, letting a be the unknown angle}$

$\bold{a+31=90}\\\text{Subtract 31 from both sides}\\\bold{a=59}$

Hope the answer - and explanation - made sense,

happy studying!!

6 0

1 year ago

The size 4 soccer ball sean's team uses should weigh no more than 0.37 kilogram and no less than 0.31 kilogram a soccer bag has

SCORPION-xisa [38]

Answer:

the most they could weigh is .74 kilos and the least would be .62

Step-by-step explanation:

7 0

2 years ago

The angle θ1\theta_1 θ 1 theta, start subscript, 1, end subscript is located in Quadrant II\text{II} II start text, I, I, end

melomori [17]

Answer:

$\dfrac{3\sqrt{13}}{11}$

Step-by-step explanation:

Given that the angle $\theta_1$ is located in Quadrant II; and

$\cos(\theta_1)=-\dfrac{2}{11}$

In Quadrant II, x is negative and y is positive.

$\cos(\theta)=\dfrac{Adjacent}{Hypotenuse},\sin(\theta)=\dfrac{Opposite}{Hypotenuse}\\$Adjacent=-2\\Hypotenuse=11\\$

To find $\sin(\theta_1)$ , we first determine the opposite angle of $\theta_1$ .

This will be done using the Pythagoras theorem.

$Hypotenuse^2=Opposite^2+Adjacent^2\\11^2=Opposite^2+(-2)^2\\Opposite^2=121-4=117\\Opposite=\sqrt{117}=3\sqrt{13}$

Therefore:

$\sin(\theta_1)=\dfrac{Opposite}{Hypotenuse}=\dfrac{3\sqrt{13}}{11}$

6 0

2 years ago