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AnnZ [28]
3 years ago
5

Help with this problem , I got 14 but I was told it’s wrong

Mathematics
1 answer:
Sav [38]3 years ago
4 0

Answer:

128 degrees.

Step-by-step explanation:

Applying the exterior angle theorem

m<x = m<z + m<y

198 - 5n = 5n + 37 + n + 7

-5n - 5n - n = 37 + 7 - 198

-11n = -154

n = 14

So remote exterior angle x = 198 - 5(14)

= 128.

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Answers should be exact decimals (please do not leave as fractions or unfinished calculations).
aksik [14]

Answer:

P(rolling the die results in a 3 or a 6)=0.3333

P(rolling the die results in not getting a 6)=0.8333

P(rolling the die results in the number being either greater than 2 or less than 5)=0.3333

P(rolling the die results in an even number or a 5)=0.6667

P( rolling the die twice results in a 6 followed by a 4)=0.0278

P(rolling the die three times results in all 6's)=0.0046

Step-by-step explanation:

a)

As the all outcomes are equally likely, so each number has equal probability of occurring.

For six sided die the sample space is {1,2,3,4,5,6} and each outcome has equal probability of 1/6.

1)

P(rolling the die results in a 3 or a 6)

P(rolling the die results in a 3 or a 6)=P(3)+P(6)=1/6+1/6=2/6=1/3

P(rolling the die results in a 3 or a 6)=0.3333

P(rolling the die results in not getting a 6)

P(rolling the die results in not getting a 6)=1-P(6)=1-1/6=5/6

P(rolling the die results in not getting a 6)=0.8333

P(rolling the die results in the number being either greater than 2 or less than 5)

number either greater than 2 or less than 5={3,4}

P(rolling the die results in the number being either greater than 2 or less than 5)=2/6=1/3

P(rolling the die results in the number being either greater than 2 or less than 5)=0.3333

P(rolling the die results in an even number or a 5)

number is an even number or a 5={2,4,5,6}

P(rolling the die results in an even number or a 5)=4/6=2/3

P(rolling the die results in an even number or a 5)=0.6667

P( rolling the die twice results in a 6 followed by a 4)

For six sided die rolled twice the sample space is

S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}.

n(S)=6²=36.

rolling the die twice results in a 6 followed by a 4={(6,4)}

P( rolling the die twice results in a 6 followed by a 4)=1/36.

P( rolling the die twice results in a 6 followed by a 4)=0.0278

P(rolling the die three times results in all 6's)

When three die are rolled the number of outcomes=n(S)=6³=216.

rolling the die three times results in all 6's={(6,6,6)}

P(rolling the die three times results in all 6's)=1/216

P(rolling the die three times results in all 6's)=0.0046

Note: All answers are rounded to four decimal places.

8 0
3 years ago
Let P (n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The goal is to sh
natulia [17]

Complete Question

Let P (n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The parts of this exercise outline a strong induction proof that P (n) is true for n ≥ 18.

Show statements P (18), P (19), P (20), and P (21) are true, completing the basis step of the proof.

Answer:

P(18) is true

P(19) is true

P(20) is true

P(21) is true

Step-by-step explanation:

a. When n = 18

18 cents can be formed using two 7cents and one 4cents

i.e. 2 * 7 + 4 = 18

So, P(18) is true

b. When n = 19

19 cents can be formed using one 7cents and three 4cents

i.e. 1 * 7 + 3 * 4 = 19

So, P(19) is true

c. When n = 20

18 cents can be formed using five 4cents

i.e. 5 * 4 = 20

So, P(20) is true

d. When n = 21

18 cents can be formed using three 7cents

i.e. 3 * 7 = 21

So, P(21) is true

7 0
3 years ago
My teacher wrote the answer on the right but he wants me to show how he did it
Airida [17]

865 is the answer of this question...

4 0
3 years ago
10 x (150-3)=(10x150) ( _x3)
Vitek1552 [10]
I'm not sure if it's 10x or 10 times a number

5 0
3 years ago
Read 2 more answers
Consider the graph of the quadratic function y=-2(x + 2)2
krek1111 [17]

Answer:

1

Step-by-step explanation:

The quadratic function

y = -2(x + 2)²  - 1

has no real zeros because its vertex is located at (-2, -1) and it opens downward (the leading coefficient, -2, is negative)

A quadratic function has one real root if its vertex has the form (x, 0). If we add 1 to our equation, we get:

y = -2(x + 2)²  - 1 + 1 = -2(x + 2)²

which has point (-2, 0) as vertex

7 0
3 years ago
Read 2 more answers
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