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rusak2 [61]
3 years ago
15

Use​ Gauss's approach to find the following sum​ (do not use​ formulas):5+11+17+23...+83

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0

Denote the sum by <em>S</em>. So

<em>S</em> = 5 + 11 + 17 + 23 + ... + 83

There's a constant difference of 6 between consecutive terms in <em>S</em>, so the 3 terms before 83 are 77, 71, and 65. So

<em>S</em> = 5 + 11 + 17 + 23 + ... + 65 + 71 + 77 + 83

Gauss's approach involves inverting the sum:

<em>S</em> = 83 + 77 + 71 + 65 + ... + 23 + 17 + 11 + 5

If we add terms in the same position in the sums, we get

2<em>S</em> = (5 + 83) + (11 + 77) + ... + (77 + 11) + (83 + 5)

and we notice that each grouped term on the right gives a total of 88. So the right side consists of several copies <em>n</em> of 88, which means

2<em>S</em> = 88<em>n</em>

and dividing both sides by 2 gives

<em>S</em> = 44<em>n</em>

<em />

Now it's a matter of determining how many copies get added. The terms in the sum form an arithmetic progression that follows the pattern

11 = 5 + 6

17 = 5 + 2*6

23 = 5 + 3*6

and so on, up to

83 = 5 + 13*6

so <em>n</em> = 13, which means the sum is <em>S</em> = 44*13 = 572.

<em />

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