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e-lub [12.9K]
3 years ago
11

If f(x)=x^2-5 and g(x)=6x then g(f(x)) is equal to

Mathematics
2 answers:
Olenka [21]3 years ago
7 0
Plug f(x) as x in g(x) and you get 6(x^2-5), which is g(f(x)) = 6x^2-30.
Romashka-Z-Leto [24]3 years ago
3 0
G(x) = 6x 

<span>g(f(x)) </span>
<span>= 6((x^2) - 5) </span>
<span>= (6x^2) - 30 
</span>
so its equal to
<span>(6x^2) - 30</span>
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Your science teacher recently gave a quiz to 28 students present in class. The class average was an 82.5. Five students that wer
irina [24]

Total students in the class who got the quiz = 28

The average of the class average was = 82.5

Five students that were absent made up the quiz after school and their scores were a 78, 89,92,99, & 63.

The formula for an average= (sum of values) / (count of values)

As the average is given as 82.5 and there were 28 students, so sum of the 28 values will be = 28\times82.5=2310

Total students of the class = 28+5(absent) = 33

For 33 students the total score was = 2310 +(78+89+92+99+63)

= 2731

So, average for 33 students will be = \frac{2731}{33} =82.757 or 82.76

So, the new class average is 82.76

3 0
3 years ago
Please help ASAP 20 pts + brainliest to right/best answer
hram777 [196]

Answer:

the answer is C

Step-by-step explanation:

The equation is just asking for you to subtract the entire function of f from the function of G. This directly translates to (x^2) - (3x +5) which cannot be simplified further than the subtraction sign. You end with x^2 - 3x -5

Hope this helps

4 0
4 years ago
(6, - 3, 1) and (8,9,-11) find the angle between the vector​
Svetllana [295]

Answer:

The angle between the two vectors is 84.813°.

Step-by-step explanation:

Statement is incomplete. Complete form is presented below:

<em>Let be (6,-3, 1) and (8, 9, -11) vector with same origin. Find the angle between the two vectors. </em>

Let \vec u = \langle 6, -3, 1 \rangle and \vec v = \langle 8,9,-11 \rangle, the angle between the two vectors is determined from definition of dot product:

\theta = \cos^{-1} \left(\frac{\vec u \,\bullet \,\vec v}{\|\vec u\|\cdot \|\vec v\|} \right) (1)

Where:

\vec u, \vec v - Vectors.

\|\vec u\|, \|\vec v\| - Norms of each vector.

Note: The norm of a vector in rectangular form can be determined by either the Pythagorean Theorem or definition of Dot Product.

If we know that \vec u = \langle 6,-3,1 \rangle and \vec v = \langle 8, 9,-11 \rangle, then the angle between the two vectors is:

\theta = \cos^{-1}\left[\frac{(6)\cdot (8) + (-3)\cdot (9) + (1)\cdot (-11)}{\sqrt{6^{2}+(-3)^{2}+1^{2}}\cdot \sqrt{8^{2}+9^{2}+(-11)^{2}}} \right]

\theta \approx 84.813^{\circ}

The angle between the two vectors is 84.813°.

6 0
2 years ago
Write an equation that represents a line that is parallel to y=3/4x and passes through the point (2,1).
Kisachek [45]
Insert the slope and point into point-slope form:-

y - 1 = 3/4(x - 2)
y = 3/4x - 6/4 + 1
y = 3/4x -  1/2
6 0
3 years ago
Can u please help me
Alchen [17]

Answer:

that answer u put is correct and r u in K12 to lol

8 0
3 years ago
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