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3 years ago

What is the difference between the mean high and mean low temperature for this 5-day period?

Mathematics

1 answer:

amid [387]3 years ago

3 0

Answer:

the mean high temperature is 71 degrees and the mean low is 31 degrees

Step-by-step explanation:

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Natali [406]

Answer:

468.75

Step-by-step explanation:

Multiply the sales by the commision as a decimal to get the commission, in this case, 1875 * 1/4 = 468.75.

8 0

3 years ago

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URGENT!!!!! Find the sine of angle Y

Andrei [34K]

Answer:

Step-by-step explanation:

10easy look at the sides it is all ways the same

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3 years ago

Verify sin^4x − sin^2x = cos^4x − cos^2x is an identity

Inga [223]

Answer:

<h2>It's an identity</h2>

Step-by-step explanation:

$\sin^4x-\sin^2x=\cos^4x-\cos^2x\\\\L_s=\sin^4x-\sin^2x=\sin^2x(\sin^2x-1)=\sin^2x(-\cos^2x)=-\sin^2x\cos^2x\\\\R_s=\cos^4x-\cos^2x=\cos^2x(\cos^2x-1)=\cos^2x(-\sin^2x)=-\sin^2x\cos^2x\\\\L_s=R_s\qquad\bold{CORRECT}$

$\text{Used:}\\\\\sin^2x+\cos^2x=1\Rightarrow\left\{\begin{array}{ccc}\cos^2x=1-\sin^2x\\\sin^2x=1-\cos^2x\end{array}\right\Rightarrow\left\{\begin{array}{ccc}-\cos^2x=\sin^2x-1\\-\sin^2x=\cos^2x-1\end{array}\right$

4 0

3 years ago

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Triangle J K L is shown. Angle J K L is 120 degrees and angle K L J is 40 degrees. The length of K L is 2 and the length of J L

Veseljchak [2.6K]

Answer:

$k \approx 5$ units$

Step-by-step explanation:

In Triangle JKL

$\angle K=120^\circ\\\angle L=40^\circ\\KL=2\\JL=k$

We want to determine the approximate value of k using the law of sines.

$\angle J+\angle K+\angle L=180^\circ $ (Sum of angles in a \triangle)\\\angle J+120^\circ+40^\circ=180^\circ \\\angle J=180^\circ-(120^\circ+40^\circ)=20^\circ$

Using Law of Sines

$\dfrac{k}{\sin K} =\dfrac{j}{\sin J} \\\dfrac{k}{\sin 120} =\dfrac{2}{\sin 20} \\k=\sin 120 \times \dfrac{2}{\sin 20}\\k=5.06\\k \approx 5$ units$

7 0

3 years ago

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Derek‘s parents are finalizing a budget for his college expenses his first year of college will cost $1000 in expenses will incr

Alenkinab [10]

Answer:

$4779

Step-by-step explanation:

First you need to write an equation to model this situation. In this case it's f(x)=1000(1.12)^x. College usually lasts 4 years, so to find the total amount of money they need to budget, you need to find the sum of f(0), f(1), f(2), and f(3).

This is roughly equivalent to 1000+1120+1254+1405, which equals 4779.

8 0

4 years ago