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melamori03 [73]
3 years ago
13

Find the area A of polygon CDEFGH with the given vertices. C(0,5), D(2,5), E(2,3), F(3,2), G(-1,2), H(0,3)

Mathematics
1 answer:
enot [183]3 years ago
8 0

Answer:

<em>The area of the polygon CDEFGH is 7</em>

Step-by-step explanation:

<u>Area of a Polygon</u>

The area of a polygon is generally calculated as the sum of the smaller areas that form its full shape, give each partial area has a known shape, like a square, rectangle, triangle, circle, etc.

The six points given in the question are plotted in the image below. They form a polygon whose area can be divided into two smaller shapes:

The area CDHE is a square of length side 2. Area of a square:

A1=L^2

The area HEFG is a trapezoid with bases lengths 4 and 2,  and height 1. Area of a trapezoid:

\displaystyle A2=\frac{b1+b2}{2}h

Calculate both areas:

A1=2^2=4

\displaystyle A2=\frac{2+4}{2}\cdot 1=3

Total Area=4+3=7

The area of the polygon CDEFGH is 7

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-3q + 12 greater than equal too 4q - 30 solve for q
valentina_108 [34]

Solving the inequality -3q+12\geq 4q-30 the value of q is q\leq 6

Step-by-step explanation:

We need to solve the inequality: -3q+12\geq 4q-30 and find value of q

Solving:

-3q+12\geq 4q-30\\Adding\,\,-12\,\,on\,\,both\,\,sides:\\-3q+12-12\geq 4q-30-12\\-3q\geq 4q-42\\Adding\,\,-4q\,\,on\,\,both\,\,sides:\\-3q-4q\geq 4q-42-4q\\-7q\geq -42\\Divide\,\,both\,\,sides\,\,by\,\,7\\\frac{-7q}{7}\geq \frac{-42}{7}\\ -q\geq -6\\Multiply\,\,both\,\,sides\,\,by\,\,-1\,\,and\,\,reverse\,\,the\,\,inequality:\\q\leq 6

So, solving the inequality -3q+12\geq 4q-30 the value of q is q\leq 6

Keywords: Solving inequality

Learn more about solving inequality at:

  • brainly.com/question/7490805
  • brainly.com/question/9590016
  • brainly.com/question/2840217

#learnwithBrainly

6 0
3 years ago
How do I find the values of these
skad [1K]
Since the triangles are similar, then 32 = x+7 those two angles are too
solve for "x"

now using proportions   \bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{JK}{18}=\cfrac{12}{12+10}

solve for JK

\bf \cfrac{\textit{small triangle}}{\textit{large triangle}}\qquad \cfrac{12}{12+10}=\cfrac{9}{9+KG}\implies 12(9+KG)=(22)9&#10;\\\\\\&#10;108+9KG=198

solve for KG

the scale factor of the perimeter of both triangles is just the same as the ratio of the sides, or \bf \cfrac{12}{12+10}

3 0
2 years ago
NEED HELP ASAP PLEASE!!!!!!!!!!!!!!!!!!
Gnoma [55]

Answer:C

Step-by-step explanation:

5 0
3 years ago
A scuba diver is at an elevation of −18 ft. She then descends 30 ft deeper. What is the scuba diver's new elevation?
sladkih [1.3K]
-18 - 30 = -48
The Scuba Diver is now 48 feet below sea level.
7 0
2 years ago
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Step-by-step explanation:

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7 0
2 years ago
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