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vesna_86 [32]
3 years ago
11

How deep is a well that takes eight cranks on the six- inch diameter windlass to raise the bucket?

Mathematics
1 answer:
Nookie1986 [14]3 years ago
6 0
In order to answer this, you would need to find the circumference of the windlass. This would represent the distance of one rotation. When you know the distance of one rotation, you would then multiply it by eight for all eight Kranks. This is knowing each crank is a complete turn. Here is the formula C= pi times the diameter. So, 3.14 x 7 is 18.84 inches for 1 crank. 18.84 inches times 8 equals 150.72 inches. This is an approximation because pi is an approximation.
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Find the sum of 2x+1 and 5x
aliya0001 [1]

Hey!

This could be rewritten as:

2x + 1 + 5x

We can add like terms together:

7x + 1

5 0
3 years ago
Read 2 more answers
The concentration of particles in a suspension is 50 per mL. A 5 mL volume of the suspension is withdrawn. a. What is the probab
kolezko [41]

Answer:

(a) 0.6579

(b) 0.2961

(c) 0.3108

(d) 240

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of particles in a suspension.

The concentration of particles in a suspension is 50 per ml.

Then in 5 mL volume of the suspension the number of particles will be,

5 × 50 = 250.

The random variable <em>X</em> thus follows a Poisson distribution with parameter, <em>λ</em> = 250.

The Poisson distribution with parameter λ, can be approximated by the Normal distribution, when λ is large say λ > 10.  

The mean of the approximated distribution of X is:

μ = λ  = 250

The standard deviation of the approximated distribution of X is:

σ = √λ  = √250 = 15.8114

Thus, X\sim N(250, 250)

(a)

Compute the probability that the number of particles withdrawn will be between 235 and 265 as follows:

P(235

                             =P(-0.95

Thus, the value of P (235 < <em>X</em> < 265) = 0.6579.

(b)

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.28

Thus, the value of P(48.

(c)

A 10 mL sample is withdrawn.

Compute the probability that the average number of particles per mL in the withdrawn sample is between 48 and 52 as follows:

P(48

                             =P(-0.40

Thus, the value of P(48.

(d)

Let the sample size be <em>n</em>.

P(48

                             0.95=P(-z

The value of <em>z</em> for this probability is,

<em>z</em> = 1.96

Compute the value of <em>n</em> as follows:

z=\frac{\bar X-\mu}{\sigma/\sqrt{n}}\\\\1.96=\frac{48-50}{15.8114/\sqrt{n}}\\\\n=[\frac{1.96\times 15.8114}{48-50}]^{2}\\\\n=240.1004\\\\n\approx 241

Thus, the sample selected must be of size 240.

5 0
3 years ago
I need help don’t understand
Tasya [4]
C. YFC hope this helps!!!
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2 years ago
You can spend at most $24 at the fair. Game tickets cost $2 each and ride tickets cost $4 each. You want to buy at least 3 game
meriva
Your game tickets are $6 total. Your ride tickets would run you about $12.

$2 x 3 = 6

$4 x 3 = 12
5 0
2 years ago
What are the opposites of 5, −2.6, 2.25, and 7 1 4 ? Enter the answers in respective order, each separated by comma.
arsen [322]
-5, 2.6, -2.25,and -714
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