Answer:
I am writing a Python function:
def is_maxheap(list):
#finds the length of the list
size=len(list)
#loop has a variable i which starts traversing from root til end of last #internal node
for i in range(int((size - 2) / 2) + 1):
if list[2 * i + 1] > list[i]: #If left child is greater than its parent then return #false
return False
if (2 * i + 2 < size and
list[2 * i + 2] > list[i]): #checks if right child is greater, if yes then #returns false
return False
return True
Explanation:
The function is_maxheap() traverses through all the internal nodes of the list iteratively. While traversing it checks if the node is greater than its children or not. To check the working of this function you can write a main() function to check the working on a given list. The main() function has a list of integers. It then calls is_maxheap() method by passing that list to the function. The program displays a message: "valid max heap" if the list represents valid max-heap otherwise it returns invalid max heap.
def main():
list = [10,7,8]
size = len(list)
if is_maxheap(list):
print("Valid Max Heap")
else:
print("Invalid Max Heap")
main()
The program along with its output is attached in a screenshot.
Answer:
student_file = {}
endf_input = '1'
for x in iter(list, 1):
name = input("Enter a student name: ")
st_id = int(input("Enter a student id number: "))
student_file[name] = st_id
endf_input = input("Add more student to file (type 1 for yes and 0 to end): ")
if endf_input == '0':
break
print("Search for Student")
search = int(input("Enter student id: "))
if search == 0:
print("Sorry, no student with id of zero.")
quit()
for key, value in student_file.items():
if value == search:
print(f"Student name: {key}")
Explanation:
The program source code uses a for loop to continuously add data to the student file dictionary structure but breaks from the loop when a zero is received as input. The program enters search mode and returns the name of the student with the searched id number.
Answer:
It helps you understand stuff faster
Explanation:
The answers are:
-the message subject
-the name of the sender
-the names of recipients
-the time and date the message was sent
Answer:
192.168.101.0 through 192.168.101.255 is the correct answer.
Explanation:
The following answer is correct because the address of the ACL entry is 192.168.101.0 and 0.0.0.255 is the wildcard mask then, the range of the IPv4 addresses is 192.168.101.0 through 192.168.101.255 that affected by the ACL.
ACL is referred as the access control list that acts as the firewall which secures the VPC network of the user.
