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Nadusha1986 [10]
3 years ago
13

This script should:

Computers and Technology
1 answer:
denis23 [38]3 years ago
5 0

Answer:

the answer is d

Explanation:

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Given coins of denominations (value) 1 = v1 < v2< … < vn, we wish to make change for an amount A using as few coins as
astraxan [27]

Answer:

Answer given below

Explanation:

a) 10 coins ( 25*8 + 1*2)

b) 14 coins (27*10 + 12*1 + 7*1 + 3*1 + 1*1)

<u></u>

<u>Source Code in C++: </u>

#include <iostream>

using namespace std;

//main function

int main()

{

int n,n1;

cout << "Enter the amount : "; //taking amount as input

cin >> n;

if(n<=0)

{

cout << "Fatal Error : Input Failure." << endl;

return 1;

}

cout << "Enter the number of denominations : "; //taking number of denominations as input

cin >> n1;

if(n1<=0)

{

cout << "Fatal Error : Input Failure." << endl;

return 1;

}

int a[n1],c[n1],sum=0; //array to keep count of each amount, and sum to store total coins

cout << "Enter the denominations in descending order : ";

for(int i=0;i<n1;i++)

{

cin >> a[i];

}

for(int i=0;i<n1;i++)

{

c[i]=n/a[i];

sum=sum+c[i];

n=n%a[i];

}

for(int i=0;i<5;i++)

{

cout << a[i] << " : " << c[i] << endl;

}

return 0;

}

3 0
3 years ago
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