Answer:
High level Language
understand
Explanation:
rocket is 0...4433456u888
Answer:
True on a web page such meta name will not appear in web view source and irrelevant information will be displayed.
Explanation:
Basically web page source is compiled version of HTML script so the end-user he or she tries to view pages system will show only in HTML.
so meta name information and active object information will not be displayed while viewing the web source code instead of that the irrelevant informant ions will be displayed and end-user cannot under anything out of the web source code.
Moreover, even the client side validation script also will not be displayed.
Only HTML will be displayed
Answer: it does – or perhaps appears to do – in the world.
Explanation:
sorry if am not right have a nice day lol
Having a filling system and keeping a clean desk is good time management tips (True)
Your wrists should be low,relaxed and resting on the frame of the keyboard while typing (False)
A correctly formatted memo will have a complimentary closing? (False)
Which professional business memo part is keyed first?
D.) TO
to type a capital letter "T" the typist will hold the right shift key with the right little finger, and then strike "t" with the left pointer (first) finger. (True)
in a standard block style letter, key the date to print ___ from the top edge of the page
D.) Double space (DS)
A search engine can help link you to information on how to format a buisness letter. (True)
Answer:
Option 1: Finds the position of the largest value in a
Explanation:
Given the codes as follows:
- int[] a = {6, 1, 9, 5, 12, 3};
- int len = a.length;
- int x = 0;
- for (int i = 1; i < len; i++)
- {
- if (a[i] > a[x])
- x = i;
- }
-
- System.out.println(x);
The code is intended to find a largest value in the array, a. The logic is as follows:
- Define a variable to hold an index where largest value positioned. At the first beginning, just presume the largest value is held at index zero, x = 0. (Line 3)
- Next, compare the value location in next index. If the value in the next index is larger, update the index-x to the next index value (Line 4 - 8). Please note the for-loop traverse the array starting from index 1. This is to enable the index-1 value can be compared with index-0 and then followed with index-2, index-3 etc.
- After completion of the for-loop, the final x value will be the index where the largest value is positioned.
- Print the position of the largest value (Line 10)
