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4 years ago

Plz help, I promise I will give Brainliest

Mathematics

2 answers:

Liula [17]4 years ago

5 0

Answer:the answer is x=-2

Step-by-step explanation:

crimeas [40]4 years ago

3 0

Answer:

Step-by-step explanation:

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Equivalent fraction of 5/6

Zarrin [17]

The list is long, but here goes:

10/12, 15/18, 20/24, 25/30, 30/36, ... and so on.

7 0

4 years ago

Read 2 more answers

Pls pls help me ASAP

Maru [420]

Answer:

1. 27.5 in.^2

2. 360 in.^2

Step-by-step explanation:

A = bh/2

A = (4 + 7)(5)/2

A = 27.5 in.^2

A = bh/2

A = (35 + 13)(15)/2

A = 360 in.^2

6 0

3 years ago

Is each number rational or<br> irrational ?<br> Select Rational or Irrational for<br> each numbers

IRINA_888 [86]

Answer:

0.5 is rational

$\sqrt{24}$

is irrational

3.42859873 is irrational

$\frac{0}{100}$

is rational

Explanation:

0.5 can be a fraction. (1/2)

Square root of 24 cant be a fraction.

3.42859873 cant be a fraction.

0/100 is a fraction.

7 0

3 years ago

Who can help me d e f thanks

12345 [234]

$y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}$

Product rule:

$y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'$

Chain and power rules:

$y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'$

Power rule:

$y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)$

Now simplify.

$y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y = \dfrac{3bx + ac}{\sqrt{ax}}$

Quotient rule:

$y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}$

$y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}$

Power rule:

$y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}$

Now simplify.

$y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}$

$y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}$

$y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}$

$y = \sin^2(ax+b)$

Chain rule:

$y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'$

$y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'$

$y' = 2a \sin(ax+b) \cos(ax+b)$

We can further simplify this to

$y' = a \sin(2(ax+b))$

using the double angle identity for sine.

7 0

2 years ago

What happens to a line as the slope approaches 0?

inessss [21]

Answer: B: It gets flatter

Step-by-step Explanation:

Slope is basically a ratio of the change in the x-value over the change in the y-value over a certain interval. It also shows how steep the line is. The higher (or further away from 0) the slope, the “steeper” the line is. If the slope is 0, the graph just looks like a horizontal line

7 0

3 years ago