First, we find the slope of the given line.
<span>3x − 4y = 7
-4y = -3x + 7
y = (3/4)x - 7/4
The slope of the given line is 3/4.
The slope of the parallel line is also 3/4.
Now we need the equation of the line that has slope 3/4 and passes through point (-4, -2),
We use the point-slope form of the equation of a line.
y - y1 = m(x - x1)
y - (-2) = (3/4)(x - (-4))
y + 2 = (3/4)(x + 4) <---- check option E. Is the fraction 3/4 not there?
y + 2 = (3/4)x + 3
y = (3/4)x + 1
4y = 3x + 4
3x - 4y = -4 <------ this is choice B.
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Answer:
11x^6y^5
Step-by-step explanation:
Given: (2x^5y^2)(4xy^3)+(x^4y^4)(3x^2y)
Use FOIL: 8x^6y^5 + 3x^6y^5
Combine like terms: 11x^6y^5
Answer:
D
Step-by-step explanation:
We will let d represent the amount of dimes Angela has.
Angel has 5 fewer quarters than twice the number of dimes.
Twice the number of dimes will be 2d.
Then, 5 fewer will yield 2d-5.
Therefore, the amount of quarters Angela has is 2d-5.
Then, the total amount of coins (dimes and quarters) together, will be:
The first part is the amount of dimes.
And the second part is, as we determined, the amount of quarters.
Therefore, our answer is D.
If you spend $6 for food, the. You have $14 left. You have enough for 56 tickets. If you’re trying to find out how much the tickets are a piece you would divide $14 by 56. This would mean the tickets are .25¢ a piece.
Not sure if that’s what you’re asking for, but hope it helps :)
Answer:
A 1.9
Step-by-step explanation:
Nt = No e^(-kt)
Where Nt is the ending amount
No is the starting amount
k is the decay constant
and t is the time
We need to determine the half life
Nt/No = e ^ -kt
1/2 of the original amount is left for 1/2 life. The time is 40 years. We will calculate k
1/2 = e ^ -k * 40
Take the natural log of each side
ln(1/2) = ln (e ^ -k * 40)
ln (1/2) = -40k
-ln(2) = -40k
ln 2 = 40k
1/40 ln (2) = k
Now we can calculate now much is left after 160 years of a 30 g sample
Nt = 30 e^(- 1/40 ln(2) * 160)
= 30 e^(-4ln(2))
= 15/8
=1.875
