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const2013 [10]
3 years ago
13

Helppppppppppppppppppp

Mathematics
1 answer:
klemol [59]3 years ago
5 0
14x^7-56x^6-126x^5+35x^4-140x^3-315x^2
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HELP ASAP ASAP HELP ASAP
exis [7]

Answer:

C = x > 6 or x < 1

Step-by-step explanation:

4x + 10 < 14

- 10. - 10

4x < 4

4x / 4 < 4 / 4

x < 1

6 0
3 years ago
GEOMETRY HELP PLS ALMOST DONE THANK U
lana [24]

Answer:

y = 4

Step-by-step explanation:

Since this is an equilateral triangle, all the sides are equal.

7y + 5 = 9y - 3

5 + 3 = 9y - 7y

2y = 8

y = 8 ÷ 2

y = 4

4 0
3 years ago
Eliza reads \large \frac{1}{7} of her book on Monday. On Tuesday and Wednesday combined, she reads three times as much as she re
lutik1710 [3]

Answer:

Eliza reads a total of 204 pages in the three days combined.

Step-by-step explanation:

From the given information, we are being told that:

Eliza reads \dfrac{1}{7} of her book on Monday.

On Tuesday and Wednesday combined, she reads thrice as much as she read on Monday.

Let assume that; Tuesday = T and Wednesday = W

Then;

T + w = 3 ( \dfrac{1}{7})

The expression to determine the total number of pages is given as:

\large \dfrac{1}{7}r+3\left(\dfrac{1}{7}r\right)

where;

r = total number of pages in the book.

Assuming that Eliza book contains a total of 357 pages. How many pages does she read in the three days combined together.

i.e.

r = 357

Then;

\implies \large \dfrac{1}{7}(357)+3\left(\dfrac{1}{7}(357)\right)

\implies 51+3(51))

\implies 51+153

= 204 pages

Thus, Eliza reads a total of 204 pages in the three days combined.

8 0
3 years ago
Match the expressions with rational exponents to their simplified forms.
Misha Larkins [42]

do it yourself

Step-by-step explanation:

6 0
3 years ago
The ratio of the side adjacent am acute angle and the hypotenuse. Adjacent/hypotenuse
diamong [38]

Answer:  The answer is cosine of that acute angle.


Step-by-step explanation:  We are to find the ratio of the adjacent side of an acute angle to the hypotenuse.

In the attached figure, we draw a right-angled triangle ABC, where ∠ABC is a right angle, and ∠ACB is an acute angle.

Now, side adjacent to ∠ACB is BC, which is the base with respect to this particular angle, and AC is the hypotenuse.

Now, the ratio is given by

\dfrac{\textup{adjacent side}}{\textup{hypotenuse}}=\dfrac{BC}{AC}=\dfrac{\textup{base}}{\textup{hypotenuse}}=\cos\textup{ of angle }ACB.

Thus, the ratio is cosine of the acute angle.

7 0
3 years ago
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