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3 years ago

HELPPPPP ME PLEASEE

Mathematics

2 answers:

aleksley [76]3 years ago

4 0

Answer: <

6.12 x 10^4 < 612,000

Step-by-step explanation:

AURORKA [14]3 years ago

3 0

Answer:

Step-by-step explanation:

because 6.12 × 10^4 = 61,200 and 612,000 is obviously a way bigger number, so greater than symbol is the correct answer.

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Verify the identity. cotangent x equals StartFraction 1 plus cosine 2 x Over sine 2 x EndFractioncot x= 1+cos2x sin2x Use the ap

lutik1710 [3]

Answer with Step-by-step explanation:

We are given that

RHS

$\frac{1+Cos2x}{Sin2x}$

We have to verify the identity.

We know that

$1+Cos2x=2Cos^2 x$

$Sin2x=2SinxCos x$

Using the formula

$\frac{2Cos^2x}{2SinxCosx}$

$\frac{Cosx}{Sinx}$

$Cot x$

By using the formula

$Cotx=\frac{Cosx}{Sinx}$

LHS=RHS

Hence, verified

6 0

4 years ago

Help me ASAP for this question

ivann1987 [24]

Answer: Y= 2x

Step-by-step explanation:

1 x 2 = 2

3.4 x 2 = 6.8

5 x 2 = 10

7 x 2 = 14

So. Y = 2x

4 0

3 years ago

The point P(7, −2) lies on the curve y = 2/(6 − x). (a) If Q is the point (x, 2/(6 − x)), use your calculator to find the slope

NARA [144]

Answer:

a) (i) $m = 2.22$ , (ii) $m = 2$ , (iii) $m = 2$ , (iv) $m = 2$ , (v) $m = 1.82$ , (vi) $m = 2$ , (vii) $m = 2$ , (viii) $m = 2$ ; b) $m \approx 2$ ; c) The equation of the tangent line to curve at P (7, -2) is $y = 2\cdot x + 12$ .

Step-by-step explanation:

a) The slope of the secant line PQ is represented by the following definition of slope:

$m = \frac{\Delta y}{\Delta x} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}$

(i) $x_{Q} = 6.9$ :

$y_{Q} =\frac{2}{6-6.9}$

$y_{Q} = -2.222$

$m = \frac{-2.222 + 2}{6.9-7}$

$m = 2.22$

(ii) $x_{Q} = 6.99$

$y_{Q} =\frac{2}{6-6.99}$

$y_{Q} = -2.020$

$m = \frac{-2.020 + 2}{6.99-7}$

$m = 2$

(iii) $x_{Q} = 6.999$

$y_{Q} =\frac{2}{6-6.999}$

$y_{Q} = -2.002$

$m = \frac{-2.002 + 2}{6.999-7}$

$m = 2$

(iv) $x_{Q} = 6.9999$

$y_{Q} =\frac{2}{6-6.9999}$

$y_{Q} = -2.0002$

$m = \frac{-2.0002 + 2}{6.9999-7}$

$m = 2$

(v) $x_{Q} = 7.1$

$y_{Q} =\frac{2}{6-7.1}$

$y_{Q} = -1.818$

$m = \frac{-1.818 + 2}{7.1-7}$

$m = 1.82$

(vi) $x_{Q} = 7.01$

$y_{Q} =\frac{2}{6-7.01}$

$y_{Q} = -1.980$

$m = \frac{-1.980 + 2}{7.01-7}$

$m = 2$

(vii) $x_{Q} = 7.001$

$y_{Q} =\frac{2}{6-7.001}$

$y_{Q} = -1.998$

$m = \frac{-1.998 + 2}{7.001-7}$

$m = 2$

(viii) $x_{Q} = 7.0001$

$y_{Q} =\frac{2}{6-7.0001}$

$y_{Q} = -1.9998$

$m = \frac{-1.9998 + 2}{7.0001-7}$

$m = 2$

b) The slope at P (7,-2) can be estimated by using the following average:

$m \approx \frac{f(6.9999)+f(7.0001)}{2}$

$m \approx \frac{2+2}{2}$

$m \approx 2$

The slope of the tangent line to the curve at P(7, -2) is 2.

c) The equation of the tangent line is a first-order polynomial with the following characteristics:

$y = m\cdot x + b$

Where:

$x$ - Independent variable.

$y$ - Depedent variable.

$m$ - Slope.

$b$ - x-Intercept.

The slope was found in point (b) (m = 2). Besides, the point of tangency (7,-2) is known and value of x-Intercept can be obtained after clearing the respective variable:

$-2 = 2 \cdot 7 + b$

$b = -2 + 14$

$b = 12$

The equation of the tangent line to curve at P (7, -2) is $y = 2\cdot x + 12$ .

7 0

3 years ago

Match each triangle with its classification

Julli [10]

A obtuse isosceles b obtuse scalene c acute isosceles

5 0

3 years ago

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What is the distance between (6, 2) and (6, -5)? A.-7 units B.3 units C.7 units D.11 units

kaheart [24]

Hey there! The correct option is A. -7 units (see photo for more info)

You can see in the photo I provided that there are 7 spaces in between (6, 2) & (6, -5) & since -5 is negative, the number of units in be will be negative.

Hope this helps you!

God bless ❤️

xXxGolferGirlxXx

7 0

4 years ago

Read 2 more answers