Newton's cooling model is ΔT = ΔTo * e ^ (-k t)
ΔTo = 200°F - 70°F = 130°F
k = 0.6
t = 2 hours
=> ΔT = 130 * e ^ (-0.6 t) = 130 * e^ (-0.6 * 2) = 130 * e ^ (-1.2)
ΔT = 39.15°F
ΔT = T - Tenvironment => T = ΔT + Tenvironment = 39.15°F + 70°F = 109.15°F ≈ 109 °F.
Answer: T = 109 °F
The roots of the quadratic equation 
are
.
Here the given quadratic equation is 
. Here 
.
The roots are
Use SOHCAHTOA. Since we are looking for the hypotenuse, you must use sine or cosine. Since, we are given the adjacent side, use cosine.
cosx=a/h
cos45=8/h
√2/2=8/h
<em>*Cross multiply*</em>
h√2=16
<em>*Divide both sides by √2*</em>
h=16/√2
<em>*Multiply by √2/√2*</em>
h=(16√2)/2
<em>*Simplify the fraction*</em>
h=8√2
Hope this helps!!
Answer:
I wanna say that its K. Sin 2x
If i'm wrong i'm so sorry
Hope i helped you in some way
