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mezya [45]
2 years ago
5

the sum of 16 numbers is 240.The average of 6 of those numbers is 10. the average of the remaining numbers is

Mathematics
1 answer:
Ivan2 years ago
4 0

Answer:

18

Step-by-step explanation:

If the average of 6 numbers is 10, then the sum of those 6 numbers is:

6 x 10 = 60

To calculate the sum of the remaining 10 numbers, subtract 60 from the total sum of all the numbers:

240 - 60 = 180

Therefore, the average of the 10 remaining numbers:

180 ÷ 10 = 18

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Can I get help with this please?
sammy [17]
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5(x+1)=20 —— distribute the 5 to the x and 1
5x+5=20 ——- subtract 5 from 20
5x=15 ———— divide by 5 from both sides
X=3 ————— answer

Second equation:
5x+1=20——— subtract 1 from 20
5x=19 ———— divide by 5 from both sides
X=19/5———— answer in fraction form
X=3.8————- answer in decimal form
8 0
3 years ago
Emily is adding 51 and 29 which steps can she use to add the numbers
frutty [35]

Answer:

51 + 29+ 80

Step-by-step explanation:

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7 0
3 years ago
150 students attended the event they were 60 cars in the student parking lot what was the ratio of students to cars?
tatyana61 [14]
150 to 60. But the more commen why to do that were to simplify it.
6 0
3 years ago
Read 2 more answers
HELP PLZ PICTURE^ Need it asap porfa
timurjin [86]

Answer:

it has one solution

Step-by-step explanation:

1.y=x-3

2. 3y-3x sub x-3 in place of y therefore

it can also be written as 3x-3x-9=9

if you add 9 to both sides 3x-3x-9+9=-9+9

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3 0
3 years ago
Drag each symbol and number to the correct location on the inequality. Not all symbols and numbers will be used. Sam initially i
galben [10]

Answer:

t \leq 18.67\ years

Step-by-step explanation:

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=?\ years\\ P=\$4,500\\ A=\$7,020\\r=0.03

The inequality that represented this situation is

P(1+rt) \leq A

substitute the values and solve for t

4,500(1+0.03t) \leq 7,020

(0.03t) \leq (7,020/4,500)-1

t \leq [(7,020/4,500)-1]/0.03

t \leq 18.67\ years

7 0
3 years ago
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