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Allisa [31]
3 years ago
6

Suppose you have a $60,000 loan with an annual percentage rate of 8% for 25 years.

Mathematics
1 answer:
amid [387]3 years ago
6 0

Answer:

The amount will be more by $30000 in the second loan.

Step-by-step explanation:

The loan of $60000 with APR 8% and for 25 years will grow to 60000 ( 1 + \frac{8 \times 25}{100} ) = 180000 dollars

So, I have to pay $180000 after 25 years.

Now, if we add $100 per month to this final amount then I have to pay $(180000 + 100 × 25 × 12) = $210000

Therefore, the loan amount will be more by $30000 in the second loan. (Answer)  

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The spinner below shows 5 equally sized slices. Tammy spun the dial 25 times and got the following results. Fill in the table be
Helen [10]

Answer:

a) 4/25, or 0.16, or 16%

b) 1/5, or 0.2, or 20%

c) The first option - the theoretical and experimental values should become closer the more trials that are performed.

Step-by-step explanation:

a) 4 of Tammy's 25 spins landed on black, so the experimental probability is 4/25, or 0.16, or 16%.

b) The spinner is split into 5 equal sections. Assuming it is fair, the chance of landing in any given section for a single spin is 1/5, or 0.2, or 20%.

c) The theoretical and experimental values should get closers the more trials you do.

For example, consider 1 coin flip vs 100. The theoretical probability of landing on a given side of a coin is 1/2, or 0.5, or 50%. With a single flip, your experimental probability will either be 0% or 100%, both off of the theoretical probability by 50%. After 100 flips however, the experimental and theoretical probabilities will be much closer to each other.

6 0
2 years ago
PLEASE ANSWER + BRAINLIEST!!<br><br> Factor completely.<br><br> 4k - 20k^9 =<br><br> 3b^2 - 108 =
Neporo4naja [7]
4k-20k^9=4k(1-5k^8)=4k\left[1^2-(k^4\sqrt5)^2\right]\\\\=4k(1-k^4\sqrt5)(1+k^4\sqrt5)=4k\left[1^2-(k^2\sqrt[4]5)^2\right](1+k^4\sqrt5)\\\\=4k(1-k^2\sqrt[4]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k\left[1^2-(k\sqrt[8]5)^2\right](1+k^2\sqrt[4]5)(1+k^4\sqrt5)\\\\=4k(1-k\sqrt[8]5)(1+k\sqrt[8]5)(1+k^2\sqrt[4]5)(1+k^4\sqrt5)

3b^2-108=3(b^2-36)=3(b^2-6^2)=3(b-6)(b+6)

Used:\ (a-b)(a+b)=a^2-b^2
7 0
3 years ago
Plz hurry hurrrrrrrrrrrrrrrrry
SIZIF [17.4K]
It is C  parallelogram and rumbus

5 0
2 years ago
Read 2 more answers
What is the square root of 9/16, 9 to the power of two
lbvjy [14]

Answer:

\frac{3}{4} , 9

Step-by-step explanation:

\sqrt{9/16} = \sqrt{9} ÷ \sqrt{16} = \frac{3}{4}

\sqrt{9^2} = \sqrt{81} = 9


3 0
3 years ago
Can Someone plz help me with this question? <br> I will mark brainliest
Gala2k [10]
The answer to your question is

No
8 0
2 years ago
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