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<u>Answer:</u>
<em>The value of x in log x + log 3 = log 18 is </em><em>6</em><em>.</em>
<u>Solution:</u>
From question, given that log x + log 3 = log 18 ---- eqn 1
Let us first simplify left hand side in above equation,
We know that log m + log n = log (mn) ----- eqn 2
Adding log m and log n results in the logarithm of the product of m and n (log mn)
By using eqn 2, log x + log 3 becomes log 3x.
log x + log 3 = log 3x ---- eqn 3
By substituting eqn 3 in eqn 1, we get
log 3x = log 18
Since we have log on both sides, we can cancel log and the above equation becomes,
3x = 18

Thus the value of x in log x + log3 = log18 is 6
Answer:
5
Explanation:
1. Find a common denominator for the three fractions. A common denominator is a number all three numbers divide into evenly. The lowest common denominator for 4, 3, and 6 is 12.
2. Find the numerators. This can be done by multiplying the current numerators by however many times the old denominator goes into the new denominator.
4 goes into 12 3 times
3 goes into 12 4 times
6 goes into 12 2 times
1 x 3 = 3
2 x 4 = 8
1 x 6 = 6
So, the fractions become:

3. Add the numerators of the new fractions and keep the denominator the same.

4. Convert the improper fraction to a mixed number.

5. Finally, add the whole numbers.
1 + 4 = 5