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Vlad [161]
3 years ago
5

There was a 6 square foot piece of wrapping paper for a birthday present

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
7 0
Can you please sent the full information that you need help with?
TiliK225 [7]3 years ago
5 0

where's the rest of question so I can help?

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Change equation to slope intercept form 2x-3y=15
meriva
Tex]y= \frac{2}{3}x-5 [/tex]
3 0
3 years ago
I got a 12 discount on a pair of jeans and a 25% discount on a t-shirt the original price of the jeans was $100 and thatof the T
Tcecarenko [31]

Answer:

$125.50

but I'm not sure

Step-by-step explanation:

100÷100=1

1×12=12

100-12=88

jeans with discount = $88

50÷100=0.5

0.5×25=12.50

5000-1250=3750

t-shirt with discount = $37.50

3750+8800=12550

6 0
2 years ago
Read 2 more answers
Can someone please help me with these two please I'll appreciate it :)
s344n2d4d5 [400]
4.

\sqrt{64}=8\\\\8\dfrac17=8.14285714...\\\\8.\overline{14}=8.14141414...\\\\ \dfrac{15}2=7,5\\\\\\ \boxed{\ \dfrac{15}2\ \ \textless \ \ \sqrt{64}\ \ \textless \ \ 8.\overline{14}\ \ \textless \ \ 8\dfrac17\ }

5.

\sqrt{18}  doesn't belong with the other three because it is irrational number
The other three can be expressed as a ratio between two <span>integers.

-\dfrac{10}2=\dfrac{-10\ }2\\\\-13.4=-13\frac4{10}=\frac{-134}{\ 10}\\\\ 22.\overline7=22\frac79=\frac{205}9\\\\\\ \sqrt{18}=\sqrt{9\cdot2}=\sqrt9\cdot\sqrt2=3\sqrt2
</span>

7 0
3 years ago
The graph of which function(s) will contain the point (3, 6)?
alekssr [168]
The first and third one
5 0
3 years ago
Read 2 more answers
Find the missing side lengths. Leave your answers as radicals in simplest form. Please help!! Due today
Nataly_w [17]

Answer:

m = 10\sqrt 3

n = 10

Step-by-step explanation:

Required

Find m and n

Considering the given angle, we have:

\sin(60) = \frac{Opposite}{Hypotenuse}

This gives:

\sin(60) = \frac{m}{20}

Make m ths subject

m = 20 * \sin(60)

\sin(60) =\frac{\sqrt 3}{2}

So, we have:

m = 20 *\frac{\sqrt 3}{2}

m = 10\sqrt 3

Considering the given angle again, we have:

\cos(60) = \frac{Adjacent}{Hypotenuse}

This gives:

\cos(60) = \frac{n}{20}

Make n the subject

n = 20 * \cos(60)

\sin(60) =\frac{1}{2}

So, we have:

n = 20 *\frac{1}{2}

n = 10

5 0
2 years ago
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