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3 years ago

Lines A and B are parallel lines cut by a transversal. Find the value of x.

Mathematics

1 answer:

myrzilka [38]3 years ago

4 0

Answer:12.33333333333

Step-by-step explanation:

8x - 2 = 14x - 76

74 = 6x

12.333 = x

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Find the circumference and area <br> r = 5 m

stira [4]

Step-by-step explanation:

Let's get our relevant base equations listed out:

d = 2r

area = pi*r²

c = πd

Thus, d=2*5m = 10m, c=π*10m=10π m, and area = 25m²*π

Feel free to ask further questions!

4 0

3 years ago

6.04 times 10 to the power of -3 as an ordinary number

Otrada [13]

6.04 x 10 ⁻³ = 0.00604

4 0

3 years ago

Read 2 more answers

Isaac made 2 quarts and 1 cup of cupcake batter. If 6 ounces of batter make one cupcake, and Isaac is making 10 cupcakes, how mu

OverLord2011 [107]

There will be 12 ounces left

4 0

3 years ago

Student is training 4 a track team during the first 3 months of the year by running 30 minutes every day, while averaging 5 mile

Novay_Z [31]

30 minutes - 5 miles;

1 hour - 10 miles

10 hours - 100 miles ...

The independent value is plotted along the x- axis ( Hours ) and the dependent variable is plotted along the y-axis ( Miles ). Also:

3 months = 90 days

90 x 1/2 hours = 45 hours

Answer: The graph B ) ( or the second one ).

4 0

3 years ago

Out of 100 people sampled, 42 had kids. Based on this, construct a 99% confidence interval for the true population proportion of

maksim [4K]

Answer:

The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

Out of 100 people sampled, 42 had kids.

This means that $n = 100, \pi = \frac{42}{100} = 0.42$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a p-value of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 2.575\sqrt{\frac{0.42*0.58}{100}} = 0.293$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 + 2.575\sqrt{\frac{0.42*0.58}{100}} = 0.547$

The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).

7 0

3 years ago