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Nesterboy [21]
3 years ago
12

HELP!!!!!!math plzzz

Mathematics
1 answer:
yan [13]3 years ago
6 0

Answer:

{0,6}

Step-by-step explanation:

You need to find all x that belong to A but do not belong to B.

0, 6 are the only ones.

Hope it helps and if it does, plzzzz mark me BRAINLIEST!!!

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15y^-11/3y^-11, show steps I need help please don't understand how to do it.
tester [92]
One may note, you never quite asked anything per se, ahemm, if you meant simplification.

\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\
-------------------------------\\\\
\cfrac{15y^{-11}}{3y^{-11}}\implies \cfrac{15}{3}\cdot \cfrac{y^{-11}}{y^{-11}}\implies 5\cdot y^{-11}\cdot y^{+11}\implies 5\cdot y^{-11+11}
\\\\\\
5y^0 \implies \boxed{5}
8 0
3 years ago
Find the value of f(–3) and g(3) if f(x) = –6x + 3 and g(x) = 3x + 21x–3.
ryzh [129]

Answer:

f(-3) = 21

g(3) = 69

Step-by-step explanation:

We have been given the following functions;

f(x) = –6x + 3

g(x) = 3x + 21x–3.

To find f(-3) , we simply substitute x = -3 in the function of f(x);

f(-3) = -6(-3) + 3

      = 21

To find g(3) , substitute x = 3 in the function of g(x);

g(3) = 3(3) +21(3) - 3

      = 69

3 0
3 years ago
Quick I need Helpppp!!<br><br> Triangle EFT is congruent to triangle JKL. What is KL, in units
Serjik [45]

Answer:

KL = 6 units.

Step-by-step explanation:

Congruent means the same or similar.

Hope this helps!

6 0
2 years ago
(-7x+8y-2z)+(-9x-y+6z)​
Svetach [21]

Answer: the answer is -16x+7y+4z

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio
disa [49]

Answer:

The  Decision Rule

Fail to reject the null hypothesis

The conclusion

 There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

   The data is  

      Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

     Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

      The  level of significance \alpha = 0.05

 Generally the null hypothesis  is  H_o  :  \mu_1 - \mu_2  = 0

                  the alternative hypothesis is   H_a  :  \mu_1 - \mu_2 >  0

Generally the sample mean for the age of  cars is mathematically represented as

        \= x_1 = \frac{\sum x_i }{n}

=>     \= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8&#10;}{27}

=>     \= x_1 = 5.56

Generally the standard deviation of age of  cars

     \sigma _1  = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }

=>  \sigma _1  = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }

=>  \sigma _1  =  3.88

Generally the sample mean for the age of taxi is mathematically represented as

        \= x_2 = \frac{\sum x_i }{n}

=>     \= x_2 = \frac{8 +8 +0  + \cdots + 4&#10;}{20}

=>     \= x_2 = 5.85

Generally the standard deviation of age of  taxi

\sigma _2  = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }

=>  \sigma _2  = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }

=>  \sigma _2  = 2.83

Generally the test statistics is mathematically represented as

   t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1}  + \frac{\sigma^2_2}{n_2} }  }

=> t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27}  + \frac{(2.83)}{20} }}  

=> t = -0.30  

Generally the degree of freedom is mathematically  represented as

   df =  n_1 + n_2 -2

    df =  27 +  20 -2

    df =  45

From the t distribution table  the P(t >  t ) at the obtained degree of freedom = 45 is  

   P(t >  -0.30 ) = 0.61722067

So  the  p-value  is

    p-value  =  P(t >  T) =  0.61722067

From the obtained values we see that the  p-value  >  \alpha hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

5 0
3 years ago
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