Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
The range is wide is the correct answer
Let
S------> The sum of the measures of the interior angles of a polygon
n-------> number of sides of a polygon
we know that
The formula to find the sum of the measures of the interior angles of a polygon is equal to
°
in this problem
°
Solve for n
therefore
the answer is
5x-1=19
1st you add the one over to the 19 and you'll get 20
then you do 5x=20
divide the 5x over to the 20 and your final answer is 4.
Answer:
800
Step-by-step explanation:
