Which postulate can be used to prove that the triangles are congruent?
1 answer:
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Answer:
(x + 1)^2 + (y + 2)^2 = 106
Step-by-step explanation:
The formula for a circle is
(x - h)^2 + (y - k)^2 = r^2
Where (h, k) is the center of the circle and r is the raadius
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The center is the midpoint of the diameter end points
(h, k) = ( (-6 + 4)/2 , (-11 + 7)/2 )
(h, k) = (-1, -2)
The radius is the distance from the center to an endpoint
Using (h, k) and Q
r^2 = (4 - -1)^2 + (7 - -2)^2
r^2 = 5^2 + 9^2
r^2 = 106
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Plug into the circle formula
(x + 1)^2 + (y + 2)^2 = 106
