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DIA [1.3K]
3 years ago
14

I don't really understand, please help!!

Mathematics
2 answers:
aivan3 [116]3 years ago
7 0

Step-by-step explanation:

In Triangle ICU,

Angle 2 = 180° - Angle 1 (Angles on a straight line)

CR = CU - RU

In Triangle ISR,

Angle 3 = 180° - Angle 4(Angles on a straight line)

SU = RS - RU

Angle 1 = Angle 4

Therefore, Angle 2 is equal to Angle 3

CU = RS

Therefore, CR is equal to SU

Triangle ICR and Triangle ISU

IC = IS

Angle 2 = Angle 3

CR = SU

Therefore, Triangle ICR and Triangle ISU are congruent (SAS congruency).

As the two triangles are congruent, Angle CIR = Angle SIU

miv72 [106K]3 years ago
4 0

Step-by-step explanation:

the proof is given above

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What is 9/16 x 2/3 (show ur work) thanks
Ilya [14]

Answer:

\displaystyle{ \frac{9}{16} \times  \frac{2}{3}  }

\displaystyle{ \frac{9 \times 2}{16 \times 3} }

\displaystyle{ \frac{18}{48} }

\displaystyle{ \frac{ \cancel2 \times  \cancel3 \times 3}{2 \times  \cancel2 \times 2 \times 2 \times  \cancel3} }

\displaystyle{ \frac{3}{2 \times 2 \times 2} }

\displaystyle{ \frac{3}{8} }

6 0
2 years ago
The students in Mr.​ Kim's class are discussing how to apply the properties of equality. Jared started with the equation 10 - 4=
iVinArrow [24]

<u>Answer</u>:

Jared is right.

<u>Explanation</u>:

proof 1:

10 - 4 = 6

6 = 6

second proof:

10-3 - 4 = 6 - 3

10 - 7 = 3

3 = 3

third proof:

10 - 4 - 3 = 6 - 3

10 - 7 = 3

3 = 3

Hence for all LHS = RHS proved and Jared is correct.

7 0
2 years ago
write the equation for the nth term of the sequence and then find the value of the 24th term: 4, 13, 22, 31, ...
julia-pushkina [17]

Answer :

nth term

an = a1 + (n-1) d

an = 4 + (9-1) 9

an = 4 + (8)9

an = 4 + 72

an = 82

24th term

an = 4 + (24-1) 9

an = 4 + (23) 9

an = 4 + 207

an = 211 is the answer

Hope it helped

4 0
3 years ago
Find y when x = 14, if y = -3 when x = 6.
ladessa [460]

Answer:

y=5

Step-by-step explanation:

6-(-3)=9

so...

14-9=5

7 0
3 years ago
Please help! Thanks in advance.
alukav5142 [94]
In this problem, we need to plug in the given x values for f(x)=0 and find a and b.

When we plug in 1, we get: 2 \times {1}^{4} - 5 \times {1}^{3} - 14 \times {1}^{2} + a \times 1 + b = 0

Simplify:
2 - 5 - 14 + a + b = 0
- 17 + a + b = 0
a + b = 17

We got our first statement about the values of the variables. If we find one more we can find those 2 variables.

We have another given root: 4.

Plug it in:
2 \times {4}^{4} - 5 \times {4}^{3} - 14 \times {4}^{2} + a \times 4 + b = 0
512 - 320 - 224 + 4a + b = 0
- 32 + 4a + b = 0
4a + b = 32

Now we have our second one. We can combine them:
a + b = 17 \\ 4a + b = 32

I use elimination method which is easier here.

Multiply the top equation by -1: - a - b = - 17 \\ 4a + b = 32

Add them up:
3a = 15

Simplify:
a = 5

Now we have a, we can plug in one of those equations to find b:
5 + b = 17
b = 17 - 5
b = 12

So, the answers are a=5 and b=12 .
6 0
3 years ago
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