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prohojiy [21]
3 years ago
12

Challenger Middle school has 800 students. Every Wednesday, 12% of the students stay after school for chess club. How many Stude

nts attend Chess Club on Wednesdays?
Mathematics
1 answer:
ahrayia [7]3 years ago
4 0

Answer: There are 96 students who attend Chess club on Wednesday.

Step-by-step explanation:

Since we have given that

Total number of students in challenger Middle school = 800

Percentage of students stay after school for chess club in Wednesday = 12%

So, Number of students who attend Chess club on Wednesday is given by

\frac{12}{100}\times 800\\\\=12\times 8\\\\=96

Hence, there are 96 students who attend Chess club on Wednesday.

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Let $ 500 be paid at the end of each quarter for 5 years. If the interest is earned rate of 13%, compounded quarterly, find the
kap26 [50]

Answer:

Future value of annuity (FV) = $13,782.12 (Approx)

Step-by-step explanation:

Given:

Periodic payment p = $500

Interest rate r = 13% = 13%/4 = 0.0325 (Quarterly)

Number of period n = 5 x 4 = 20 quarter

Find:

Future value of annuity (FV)

Computation:

Future\ value\ of\ annuity\ (FV)=p[\frac{(1+r)^n-1}{r} ] \\\\Future\ value\ of\ annuity\ (FV)=500[\frac{(1+0.0325)^{20}-1}{0.0325} ] \\\\Future\ value\ of\ annuity\ (FV)=13,782.1219 \\\\

Future value of annuity (FV) = $13,782.12 (Approx)

7 0
2 years ago
What two partial products would you add to find 513 x 46
Afina-wow [57]
First, let me do the Mathematical part of that, and then I shall explain the theory behind it.

Mathematical part:
We are going to multiply 513 with 46. So the two partial products that we are going to choose are 40 and 6.

Multiply 513 with 6 first.

    513
    x46
--------------------------
      18 (as 6*3 = 18)
      60 (as 6*10 = 60; In 513, the digit at tenths place is 1, so 1*10=10)
  3000 (as 6*500 = 3000; In 513, 5 is at hundredth place, so 5*100=500)
    120 (as 40*3 = 120; since 4 is at the tenth place, so 4*10=40)
    400 (as 40*10 = 400)
20000 (as 40*500 = 20000)
--------------------------
23598 (Add all of them)


Theory:
As you can see above that we have chosen the two partial products individually which are 6 and 40. Since 4 in 46 is in tenth place, we have to consider it 40 (since 4*10 = 40). One by one, we first multiply 6 with 513. Then we move to the tenth place, and multiply 513 with 40. At the end, we have added all the results we found after multiplication.

Check: If we check the multiplication result by using the calculator, we would get the same result (23598).

Another Method (instant):
513 * (40+6) = (513*40) + (513*6) = 23598.
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Answer:

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