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hram777 [196]
3 years ago
12

Nine fifths-three fifths

Mathematics
2 answers:
m_a_m_a [10]3 years ago
7 0
Can you please explain what question you have?
Feliz [49]3 years ago
3 0
6:5 it's actually a ritio
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For the equation, 2x + 6 = 3x - 10, what is the solution
geniusboy [140]

Answer: x=16

Step-by-step explanation:

2x+6=3x-10

Subtract 6 on both sides

2x+6-6=3x-10-6

2x=3x-16

Subtract 3x on both sides

2x-3x=3x-16-3x

-x=-16

Divide -1 on both sides

\frac{-x}{-1}=\frac{-16}{-1}

x=16

7 0
3 years ago
HELP PLZZZZZZZZZ!!!!!!!!!!
Nostrana [21]
I’m pretty sure it’s d
7 0
3 years ago
Read 2 more answers
Write a formula for function f in terms of function g.
emmasim [6.3K]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}


so hmm if you notice, your f(x) there, looks just like g(x), but is "shifted horizontally" by about 9 units to the right

that simply means, based on that template above, that C/B = -9, and we can simply make B = 1  and C = -9, and we get C/B = -9/1 which is -9

thus   \bf \begin{array}{llcll}
f(x)=g(&1x&-9)\\
&\uparrow &\uparrow \\
&B&C
\end{array}\iff f(x)=g(x-9)
7 0
3 years ago
1/x&lt;4x<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bx%7D%20%20%3C%204x" id="TexFormula1" title=" \frac{1}{x} &lt
liraira [26]

Answer:

x>\frac{1}{2} \\x

Step-by-step explanation:

If we solve for 'x' variable, its recommended to multiply 'x' variable in both sides of inequality:

we have \frac{1}{4}< x^{2} \\

This is a quadratic equation, two answer are going to be obtained from here.

since \sqrt{x^{2} } = |x|

Applying square roots to both sides of inequality sign we wil have the following

\sqrt{\frac{1}{4} } < \sqrt{x^{2} }

This leaves to the following

\frac{1}{4}

remember that |x|= +/ - x

so

x>\frac{1}{2} \\x

6 0
4 years ago
3. Write 13 tens as hundreds<br> and tens.
Alecsey [184]

Answer:

1 hundred and 3 tens

Step-by-step explanation:

I assume you mean 130 as hundreds and tens and the answer to that would be 1 hundred and 3 tens.

4 0
3 years ago
Read 2 more answers
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