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Softa [21]
3 years ago
5

describe a real world situation that is modeled by dividing two fractions or mixed numbers help me please

Mathematics
1 answer:
skad [1K]3 years ago
4 0
<span> your recipe calls for 1 1/2 cups of flour. you are only making half of this recipe.How much flour do you need?
</span>
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Can anyone explain tonme how to do this please?
Mars2501 [29]
C is right. She has partially completed the construction. Her next step is to use the arc markings to determine the radius to construct the circle.
4 0
3 years ago
Read 2 more answers
If f(z)=m^z - n^z, and f(1)=2, f(2)=8. Find f(3).
Marina CMI [18]
If f(z)=m^z - n^z <span>and f(1)=2, f(2)=8
then
m -  n = 2 so m = n + 2 
m^2 - n^2 = 8

substitute </span>m = n + 2  into m^2 - n^2 = 8

so
m^2 - n^2 = 8
(n + 2)^2 - n^2 = 8
n^2 + 4n + 4 - n^2 = 8
4n = 4
  n = 1

m = n + 2 = 1 + 2 = 3

so f(z) = 3^z - 1^z

if z = 1 the f(1) = 3^1 - 1^1 = 2
if z = 2 the f(2) = 3^2 - 1^2 = 9 - 1 = 8
if z = 3 the f(3) = 3^3 - 1^2 = 27 - 1 = 26

answer
f(3) = 26

3 0
3 years ago
Darnells car used 8 gallons to travel 340. Miles after a machanic worked on the car it used 7 gallons of gasoline to travel 350
Likurg_2 [28]

Answer:

 What we are going to do for this case is find the cost for each case:

 Cost to run the car before the mechanic worked on it:

 

 Cost to run the car after the mechanic worked on it:

 

 The difference between both cases is:

 

 Answer:

 It cost to run the car after the mechanic worked on it 0.01 $ / mile less than before the mechanic worked on it.

Read more on Brainly.com - brainly.com/question/2528459#readmoreStep-by-step explanation:

5 0
3 years ago
In ΔPQR, r = 4.9 cm, ∠R=21° and ∠P=104°. Find the length of p, to the nearest 10th of a centimeter.
Galina-37 [17]

Answer:7 +7=14/8Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the answer to this question I can’t work it out Ni=n02(yi-yo)/t2
mr_godi [17]

Changing the subject of an equation involves solving for another variable in the equation

The equation of t is t=\frac{\sqrt{y_i-y_o}}{N}

<h3>How to change the subject of the equation</h3>

The equation is given as:

N=\sqrt[2]{\frac{y_i-y_o}{t^2}}

Rewrite the equation as:

N=\sqrt{\frac{y_i-y_o}{t^2}}

Evaluate the square root of t^2

N=\frac{\sqrt{y_i-y_o}}{t}

Multiply both sides by t

Nt=\sqrt{y_i-y_o}

Make t the subject, in the above equation

t=\frac{\sqrt{y_i-y_o}}{N}

Hence, the equation of t is t=\frac{\sqrt{y_i-y_o}}{N}

Read more about subject of formula at:

brainly.com/question/657646

6 0
2 years ago
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