With such a high mean an outlier that is of the value of ten would cause the mean of the data set to decrease.
Step-by-step explanation:
by going down your screen after you ask a question and the answer is there i guess i dunno
Negative is smallest so 4/5 is smallest
then comparre 5/6 to 7/9
make bottom number same
5/6 times 3/3=15/18
7/9 times 2/2=14/18
comare 15/18 to 14/18
15/18>14/19
therefor 7/9<5/6
order is
-4/5, 7/9, 5/6
Answer:
Step-by-step explanation:
y = 2x + 3 {y = mx + b}
In Function A, rate of change is 2
Function B:
Rate of change = Change in y÷ change in x
![= \frac{11-7}{0-[-1]}\\\\=\frac{11-7}{0+1}\\\\=\frac{4}{1}\\\\= 4](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B11-7%7D%7B0-%5B-1%5D%7D%5C%5C%5C%5C%3D%5Cfrac%7B11-7%7D%7B0%2B1%7D%5C%5C%5C%5C%3D%5Cfrac%7B4%7D%7B1%7D%5C%5C%5C%5C%3D%204)
In function B, rate of change is 4
Least: Function A
Greatest: Function B
37x = 12 to log form is log37(12)
log 12/log 37 = 0.68
