Answer:
- x = 0 or 1
- x = ±i/4
- x = -5 (twice)
Step-by-step explanation:
Factoring is aided by having the equations in standard form. The first step in each case is to put the equations in that form. The zero product property tells you that a product is zero when a factor is zero. The solutions are the values of x that make the factors zero.
1. x^2 -x = 0
x(x -1) = 0 . . . . . x = 0 or 1
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2. 16x^2 +1 = 0
This is the "difference of squares" ...
(4x)^2 - (i)^2 = 0
(4x -i)(4x +i) = 0 . . . . . x = -i/4 or i/4 (zeros are complex)
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3. x^2 +10x +25 = 0
(x +5)(x +5) = 0 . . . . . x = -5 with multiplicity 2
Answer:
the answer is 511 I think
Step-by-step explanation:
percentage * your amount / 100
(70 * 730) / 100
Amount = 511
Answer:
i think it is many but i am not sure
Step-by-step explanation:
Answer:
I don't know
Step-by-step explanation:
because I don't see the pattern
Prime factors are factors of a composite number that are indivisible except by the number 1 or the number itself. The answers to your questions are the following:
1. Yes, it is possible especially for very large numbers.
2&3. No, because as mentioned previously, the default prime factors of numbers are 1 and the number itself. For example, 2 is a prime number. Its factors are 1 and 2.
4. Prime factorization are useful in fields of encryption. They make use of the basic prime numbers for the arithmetic modulus with the general equation: n=pq.
