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3 years ago

10

Find g(1) if g(x) = x^2 + 1.

2 answers:

poizon [28]3 years ago

5 0

Answer:

2

Step-by-step explanation:

g(1) is substituted for x.

g(x)=1^2+1

g(x)=1+1

g(x)=2

Natasha_Volkova [10]3 years ago

4 0

Answer:

2

Step-by-step explanation:

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2 years ago

Suppose that the function g is defined, for all real numbers, as follows.

svetoff [14.1K]

Answer:

<em>a) g(-2) = 0</em>

<em>b) g(-1) =1</em>

<em>c) g(4) = 2</em>

Step-by-step explanation:

Given data

$g(x) = \frac{-1}{4x+1} if x < -2$

$g(x) = - (x+1)^{2} +1 if -2\leq x\leq 2$

$g(x) = 2 if x >2$

<u><em>Step( i )</em></u>:-

$g(x) = - (x+1)^{2} +1 if -2\leq x\leq 2$

put x = -2

$g(-2) = -(-2+1)^{2} +1 = -(-1)^{2}+1 = -1+1 =0$

<em>g(-2) = 0</em>

<u><em>Step(ii)</em></u>:-

$g(x) = - (x+1)^{2} +1 if -2\leq x\leq 2$

Put x = -1

$g(-1) = -(-1+1)^{2} +1 = -(0)^{2}+1 = -0+1 =1$

<em>g(-1) =1</em>

<u><em>Step(iii)</em></u>:-

$g(x) = 2 if x >2$

<em>g(4) = 2</em>

<em></em>

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3 years ago