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Kitty [74]
4 years ago
10

Find g(1) if g(x) = x^2 + 1.

Mathematics
2 answers:
poizon [28]4 years ago
5 0

Answer:

2

Step-by-step explanation:

g(1) is substituted for x.

g(x)=1^2+1

g(x)=1+1

g(x)=2

Natasha_Volkova [10]4 years ago
4 0

Answer:

2

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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Clarita is a single taxpayer with two dependent children, ages 10 and 12. Clarita
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Step-by-step explanation:

1. Clarita's total income =

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According to USA (Pub.503.,)

you exclude or deduct dependent care benefits provided by a dependent care benefit plan, the total amount you exclude or deduct must be less than the dollar limit for qualifying expenses (generally, $3,000 if one qualifying person was cared for or $6,000 if two or more qualifying persons were cared for). (If two or more qualifying persons were cared for, the amount you exclude or deduct will always be less than the dollar limit because the total amount you can exclude or deduct is limited to $5,000.

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5 0
3 years ago
A large bathtub contains 425 gallons of water. after 5 minutes of draining, it has lost 32% its volume of water.
SOVA2 [1]

Answer:

84.93

Step-by-step explanation:

7 0
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Whoever has the best answer gets the brainliest answer!:)
Korvikt [17]
Since the length is 10 in. You must multiply it by \frac{1}{5} and then multiply by \frac{1}{2}. The reason for this is because if you divide ten by 5 it will be 2, then if you divide 2 by 2 it will be 1.
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3 years ago
1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by
Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0
3 years ago
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