Question

A box is filled with 8 blue cards, 8 yellow cards, and 2 green cards. A card is chosen at random from the box. What is the probability that the card is not yellow?

Answer 1

The probability that the card is not yellow is $\frac{5}{9}$

Solution:

The probability of an event is given as:

$Probability = \frac{ \text{ number of favorable outcomes }}{ \text{ total number of possible outcomes }}$

From given,

A box is filled with 8 blue cards, 8 yellow cards, and 2 green cards

Total number of possible outcomes = 8 + 8 + 2 = 18

Favorable outcome = card is not yellow

Favorable outcome = card is blue or green = 8 + 2 = 10

Therefore,

$Probability = \frac{10}{18}\\\\Probability = \frac{5}{9}$

Thus the probability that the card is not yellow is 5/9

Answer 2

The probability that the chosen card is not yellow  =   $\frac{5}{9}$

Step-by-step explanation:

Step 1 :

Given,

Number of blue cards in the box = 8

Number of yellow cards in the box = 8

Number of green cards in the box = 2

Hence total number of cards =  18

We need to find the probability that the chosen card is not yellow.

Step 2 :

Probability that the selected card is yellow = $\frac{8}{18}$ = $\frac{4}{9}$  [since the favorable outcome = 8 and total outcome = 18]

Hence the probability of chosen card not being yellow  = 1 -  $\frac{4}{9}$ =  $\frac{5}{9}$

Step 3 :

Answer :

The probability of chosen card not being yellow  =   $\frac{5}{9}$