“If the minimum wage rate is higher than the equilibrium wage rate, fewer people will be hired because the cost of labor is too
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With a mean of 1000 and a standard deviation of 600, the probability that the demand is going to be withing 25 percent of its forecast is 0.3230.
a. Mean = 1000
sd = 600
p(1000x 1-25%) - p(1000x 1+25%)
using the z test
d-μ/σ
find values using excel sheet formula
NORMSDIST(0.4167) - NORMSDIST(-0.4167)
=m0.6615 - 0.3385
= 0.3230
<h3>b. The probability that the forecast would be more than 40 percent</h3>1000x 1+40%
= p(D>1400)
= 1- NormDist(0.667)
= 0.225
c. Cu = 121-72 = 49
Co = 72.50 = 22
The critical ratio calculation
49/22 +49 = 0.6901
Normsinv(0.6901) = 0.496
1000+0.496x600
= 1297
The units that Flextrola has to order is 1297.
<h3>d. The expected sales of Flextrola</h3>1200-1000/600
= 0.3333
loss function from z = 0.333 is 0.254
600x0.254 = 152. 4
1000-152.4 = 847.6
the expected sales are 847.6
e 1200- 847.6
= 352. 4
The units of inventory that can be sold is 352.4
Read more on inventory here: brainly.com/question/24868116
Answer:
3.69
Explanation:
We know,
The productivity in sales revenue/labor expense =
Given,
Sales revenue = Units sold × Sale price per unit
Sales revenue = 1,217 units × $1,700
Sales revenue = $2,068,900
labor expense = Total labor hours × wage rate per hour
labor expense = 46,672 × $12
labor expense = $560,064
Putting the values into the formula, We can get,
The productivity in sales revenue/labor expense =
The productivity in sales revenue/labor expense = 3.69