Hi student, let me help you out! :)
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
We are asked to find the two integers, given that they are consecutive, and their sum is 65.

- Consecutive integers are right next to each other, like 12 and 13. or 65 and 66.
Let the first integer be x, and let the second integer be x+1.
Their sum is 65. Let's set up our equation:

Combine like terms:

Subtract 1 from both sides of the equal sign:

Divide both sides by 2:

To find the second integer, subtract the first integer from the sum of the two integers:


The integers are: 33 and 32.
Hope it helps you out! :D
Ask in comments if any queries arise.
#StudyWithBrainly
~Just a smiley person helping fellow students :)
I can’t really see please text it
Answer:
1. 208 in^2
Step-by-step explanation:
1. We can break the shape up into a rectangle in the middle and 2 triangles on either side of said rectangle.
The dimensions of the rectangle are 8 in by 20 in, and we only know one leg of the triangle as well as the hypotenuse.
If we know one leg and the hypotenuse we can use the pythagorean theormed to sovle for the other side and get 6 in.
So we have
(8 * 20) + 2((1/2)(6)(8))
160 + 48
208 in^2