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3 years ago

Reduce 7y + 2y 2 - 7 by 3 - 4y.

Mathematics

2 answers:

CaHeK987 [17]3 years ago

7 0

$2y^2+11y-10$

N76 [4]3 years ago

5 0

Reduce 7y + 2y^2 - 7 by 3 - 4y.
its mean subtract 3 - 4y from 7y + 2y^2 - 7
so
7y + 2y^2 - 7 - (3 - 4y)
= 2y^2 + 7y -7 - 3 + 4y
= 2y^2 + 11y - 10

hope it helps

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Can someone pls help me solve thiss

Nikolay [14]

Answer:

The value of x = 9

Step-by-step explanation:

Given the angles of the triangle

(13x+2)°

(5x-7)°

(3x-4)°

We know that the sum of angles of a triangle is 180°.

Therefore,

(13x+2)° + (5x-7)° + (3x-4)° = 180°

13x+2 + 5x-7 + 3x-4 = 180°

21x + 2 - 11 = 180°

21x - 9 = 180°

21x = 180° + 9

21x = 189

divide both side sby 21

21x/21 = 189/21

x = 9

Therefore, the value of x = 9

3 0

3 years ago

Answer asap

Lana71 [14]

Two figure in front

h=16+17 = 33 m
l=18 m
width = 13 m
Volume = lwh = 18*13*33 =7722 m^2

Two figures at the back

h=16 m
l=18+18 =36 m
width = 15 m

Volume = lwh =36*15*16 =8640 m^2

Total volume = 7722+8640 = 16362 m^2

5 0

3 years ago

Simplification -4a+b+3c+3a-3b+c

damaskus [11]

Answer:

-a+-2b+4c

Step-by-step explanation:

Combine like terms

-4a+ 3a= -a

b+ -3b= -2b

3c+ c= 4c

7 0

3 years ago

If Aldo puts 400 into a savings account that paid an interest rate of 5.4 percent What was the total amount in his account at th

Ne4ueva [31]

Answer:

$\$421.60$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$A=P(1+rt)$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=1\ year\\ P=\$400\\ A=?\\r=5.4\%=5.4/100=0.054$

substitute in the formula above

$A=400(1+0.054*1)$

$A=400(1.054)$

$A=\$421.60$

Remember that Interest is equal to

$I=A-P$

$I=\$421.60-\$400=\$21.60$

5 0

3 years ago

The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly

Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between $\\ (\mu - 6\sigma)$ and $\\ (\mu + 6\sigma)$ . It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

$\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027$

For those with defects operating at a 6 sigma level, the probability is:

$\\ 1 - p = 1 - 0.999999998027 = 0.000000001973$

Similarly, for finding no defects in a 5 sigma level, we have:

$\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697$ .

The probability of defects is:

$\\ 1 - p = 1 - 0.999999426697 = 0.000000573303$

Well, the defects present in a six sigma level and a five sigma level are, respectively:

$\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}$

$\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}$

Then, comparing both fractions, we can confirm that a 6 sigma level is markedly different when it comes to the number of defects present:

$\\ {6\sigma} \approx \frac{2}{10^9}$ [1]

$\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9}$ [2]

Comparing [1] and [2], a six sigma process has 2 defects per billion opportunities, whereas a five sigma process has 600 defects per billion opportunities.

8 0

3 years ago