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3 years ago

Reduce 7y + 2y 2 - 7 by 3 - 4y.

Mathematics

2 answers:

CaHeK987 [17]3 years ago

7 0

$2y^2+11y-10$

N76 [4]3 years ago

5 0

<span>Reduce 7y + 2y^2 - 7 by 3 - 4y.
</span>its mean subtract 3 - 4y from 7y + 2y^2 - 7
so
7y + 2y^2 - 7 - (3 - 4y)
= 2y^2 + 7y -7 - 3 + 4y
= 2y^2 + 11y - 10

hope it helps

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The Target heart rate for fit person of age a exercising at p percent of his or her heart rate is determined by the expression 1

natita [175]

Answer: 9p - 1.5a

Step-by-step explanation:

Your maximum heart rate is about 220 minus your age. But it varies base on age category.

Target heart rate during moderate intensity activities is about 50-70% of maximum heart rate.

According to the question;

Target heart rate for

women = 1/2p(418-4a)

= 209p - 2a ....... (1)

men = 1/2p(400-a)

= 200p - 0.5a .......(2)

To find the difference between the target heart rates for a fit woman and a fit man, take equation 1 from equation 2

(209p - 2a) - (200p - 0.5a)

209p - 2a - 200p + 0.5a

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3 years ago

HELP NOW!!!!

VMariaS [17]

Using the concept of probability and the arrangements formula, there is a

0.002 = 0.2% probability that the first 8 people in line are teachers.

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A probability is the <u>number of desired outcomes divided by the number of total outcomes.</u>
The order in which they are positioned is important, and all people will be positioned, and thus, the arrangements formula is used to find the number of outcomes.

The number of possible arrangements from a set of n elements is given by:

$A_n = n!$

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The desired outcomes are:

First 8 people are teachers, in <u>8! possible ways.</u>
Last 4 are students, in <u>4! possible ways.</u>

Thus, $D = 8! \times 4!$

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For the total outcomes, <u>number of arrangements of 12 people</u>, thus:

$T = 12!$

The probability is:

$p = \frac{D}{T} = \frac{8! \times 4!}{12!} = 0.002$

0.002 = 0.2% probability that the first 8 people in line are teachers.

A similar problem is given at brainly.com/question/24650047

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3 years ago

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2 years ago

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The similar circles P and Q can be made equal by dilation and translation

The horizontal distance between the center of circles P and Q is 11.70 units
The scale factor of dilation from circle P to Q is 2.5

<h3>The horizontal distance between their centers?</h3>

From the figure, we have the centers to be:

P = (-5,4)

Q = (6,8)

The distance is then calculated using:

d = √(x2 - x1)^2 + (y2 - y1)^2

So, we have:

d = √(6 + 5)^2 + (8 - 4)^2

Evaluate the sum

d = √137

Evaluate the root

d = 11.70

Hence, the horizontal distance between the center of circles P and Q is 11.70 units

<h3>The scale factor of dilation from circle P to Q</h3>

We have their radius to be:

P = 2

Q = 5

Divide the radius of Q by P to determine the scale factor (k)

k = Q/P

k = 5/2

k = 2.5

Hence, the scale factor of dilation from circle P to Q is 2.5