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nikklg [1K]
3 years ago
8

Four less than the product of ten and a number is eleven. is

Mathematics
1 answer:
nikitadnepr [17]3 years ago
3 0

Answer:

If written in algebraic form it is, 10x - 4 = 11

Step-by-step explanation:

Four less ( minus 4 ) than the product of ten and a number ( 10 times x ) is eleven ( equal to 11 ).

Hopefully this helps!

Brainliest please?

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4.6(x - 3) = -0.4x + 16.2
kolbaska11 [484]

Hey!

-----------------------------------------------

Steps To Solve:

4.6(x - 3) = -0.4x + 16.2

~Distributive property

4.6x - 13.8 = -0.4x + 16.2

~Add 0.4 to both sides

4.6x - 13.8 + 0.4= -0.4x + 16.2 + 0.4

~Simplify

5x - 13.8 = 16.2

~Add 13.8 to both sides

5x - 13.8 + 13.8 = 16.2 + 13.8

~Simplify

5x = 30

Divide 5 to both sides

5x/5 = 30/5

~Simplify

x = 6

-----------------------------------------------

Answer:

\large\boxed{x~=~6}

-----------------------------------------------

Hope This Helped! Good Luck!

8 0
3 years ago
Read 2 more answers
What is the range of the function y = x ^2?
VikaD [51]

Range: [0, ∞), {y|0 ≤ y}

3 0
3 years ago
PLEASE HELP! A) 6,135º C B) 6,681º C C) 502º C D) 47º C
Arada [10]

Answer: 47°C

Step-by-step explanation:

Since we are given the velocity, all we have to do is plug in 358 for v and solve for t.

358=20\sqrt{273+t}                    [divide both sides by 20]

17.9=\sqrt{273+t}                        [square both sides to cancel out square root]

320.41=273+t                       [subtract both sides by 273]

t=47.41

Now that we know the temperature is 47.41°C, we know our answer choice is D.

8 0
3 years ago
What is the difference between intersecting and perpendicular lines? Can two lines exist that are not intersecting or parallel?
sertanlavr [38]
Intersecting lines are lines that meet at some point while perpendicular lines are intersecting lines that makes a right angle at the point of intersection.

Two line can either be intersecting or perpendicular. It is not possible to have two line that is neither intersecting or parallel.
7 0
3 years ago
A 2 kg metal cylinder is supplied with 1600J of energy to heat it from 5°C to 13°C. What is the specific heat capacity of the me
Neporo4naja [7]

Answer:

c = 100\,\frac{J}{kg\cdot ^{\circ}C}

Step-by-step explanation:

According to the First Law of Thermodynamics, the heat received by the metal cylinder is equal to the change in the internal energy. That is:

Q = \Delta U

Q = m \cdot c \cdot \Delta T

The specific heat is clear in the previous expression and finally computed:

c = \frac{Q}{m\cdot \Delta T}

c = \frac{1600\,J}{(2\,kg)\cdot (13^{\circ}C-5^{\circ}C)}

c = 100\,\frac{J}{kg\cdot ^{\circ}C}

6 0
3 years ago
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