Answer:
<u>Triangle ABC and triangle MNO</u> are congruent. A <u>Rotation</u> is a single rigid transformation that maps the two congruent triangles.
Step-by-step explanation:
ΔABC has vertices at A(12, 8), B(4,8), and C(4, 14).
- length of AB = √[(12-4)² + (8-8)²] = 8
- length of AC = √[(12-4)² + (8-14)²] = 10
- length of CB = √[(4-4)² + (8-14)²] = 6
ΔMNO has vertices at M(4, 16), N(4,8), and O(-2,8).
- length of MN = √[(4-4)² + (16-8)²] = 8
- length of MO = √[(4+2)² + (16-8)²] = 10
- length of NO = √[(4+2)² + (8-8)²] = 6
Therefore:
and ΔABC ≅ ΔMNO by SSS postulate.
In the picture attached, both triangles are shown. It can be seen that counterclockwise rotation of ΔABC around vertex B would map ΔABC into the ΔMNO.
Answer:
Step-by-step explanation:
9x+3y
Answer:
∠A = 70°
Step-by-step explanation:
I'm... guessing this is what you mean? It would've been helpful if you'd provided pictures.
Since all parallelograms consist of two pairs of vertically opposite angles, ∠A and ∠C are equivalent.
Which means that 2x + 50 = 3x + 40.
In which you solve the equation.
2x + 50 = 3x + 40
-2x -2x
50 = x + 40
-40 -40
x = 10
Now, to find ∠A, substitute x into the equation:
∠A = 2x + 50
x = 10
∠A = 20 + 50
∠A = 70
Hence, ∠A = 70°
Given:
- total number of masks= 200
- cost of 1 mask= Rs. 5
so, total cost fir 200 masks=
200×5
= 1000
therefore, Joe paid Rs. 1000 altogether.
Answer:
19 ft
Step-by-step explanation:
Apparently, we are to assume the figure is a kite and that the diagonals cross at right angles. The area of such a figure is ...
A = (1/2)(d1)(d2)
Filling in the numbers, we get ...
114 ft^2 = (1/2)(d1)(12 ft)
d1 = (114 ft^2)/(6 ft) . . . . divide by the coefficient of d1
d1 = 19 ft
