Answer:
b. UDP
Explanation:
Uridine diphosphate glucose (UDP) is a nucleotide sugar involved in galactose metabolism. In this reaction, the galactose 1-phosphate uridylyltransferase (GALT) enzyme transfers a phosphate group from UDP-glucose to galactose 1-phosphate in order to convert galactose into glucose
It would be capillary action
Wow this is phrased rather difficult.
My answer would definitely would probably be "C".
Remember that the 10% rule only applies towards energy. Since energy is no indication of healthiness all trophic levels are healthy in their own way.
<span>I think you're talking about a stereoscopic microscope</span>
Ventilation maintains a steep concentration gradient, blood at the exchange surface usually has lower O2 and higher CO2 content than the air (of for fish, the water) at the exchange surface. This is what allows for diffusion of O2 into the blood and CO2 out of the blood. Multicellular organisms have a greater number of cells so will have a higher energy demand than single cellular organisms, this demand can only be met by allowing the cells to respire, a ventilation system brings oxygen molecules which are a raw product of respiration into the hemoglobin of the blood to be transported to tissues. As surface area : volume ratio is very low so if there was no ventilation system and the organism instead relied on exchange of materials through the exposed skin it would be very difficult to met the high energy demand as less O2 and CO2 would be able to be exchanged.
