ATP and ADP both play a role in cellular reactions involving energy. How are these two molecules related?

Wind has no effect on a plants respiration rate

valentina_108 [34]

Wind has no effect on a plants respiration rate True

Where sugars are formed are referred to as the sink True

Both the xylem and phloem do not use any plant energy to translocation materials True

The amount of humidity in the air will affect transpiration True

The rate of transpiration reduces as the relative humidity of the air around the plant increases. Compared to more saturated air, dryer air makes it simpler for water to evaporate. A plant's transpiration rate will rise when air movement around it increases.

<h3>What about plants respiration?</h3>

Water vapor is lost via the process of transpiration through a plant's stomata.
When it's very hot outside, the plant loses water vapor to cool down, and water from the stem and roots flows up or is "drawn" into the leaves.
In addition, plant transpiration contributes significantly to the leaf's energy balance by providing evaporative cooling.
Additionally, the movement of water and nutrients from the roots to the shoots is accelerated by transpiration.
Plants use transpiration for a variety of purposes.
The direct effects of transpiration include controlling the plant's temperature and supplying water for photosynthesis.
Additionally, it facilitates the movement of glucose and nutrients through the plant's vascular tissues.
Plants lose water through a process known as transpiration.
A plant's roots can collect up to 99.5% of the water that the plant transpires, which is not used for growth or metabolism.
For the surroundings to remain wet, transpiration is necessary.

Learn more about plants respiration here:

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6 0

1 year ago

In a small cramped kitchen, you and some friends are preparing a spaghetti dinner. the water is boiling and the pasta is now rea

DerKrebs [107]

In a small cramped kitchen, you and some friends are preparing a spaghetti dinner. the water is boiling and the pasta is now ready to be carried to the sink to drain. you pick up the pot of bubbling pasta water and start in the direction of the sink. the pot holder slips slightly, causing the water to splash onto your arm. the scalding water burns your forearm. you are experiencing a lot of pain, with a red, blistering burn on your arm.

The appropriate first response will be to cool the affected arm under running water and application of ice pack. The cold temperatures will lower the pain that is being felt.

6 0

3 years ago

The highly specialized blood cell whose function is oxygen transportation is

spayn [35]

A red blood cell's function is to transport oxygen.

5 0

3 years ago

2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents =<u> </u> $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago

Which technology are environmental scientists using in conjunction with electronic collars to track the movements of polar bears

Afina-wow [57]

Environmental scientists are using GPS ( It is effective but expensive) aerial monitoring (Quick but not the easiest), RFID tags, (mostly for long-term monitoring) and hidden cameras are used to study polar bear behavior without interruption to their environment.

8 0

3 years ago