Answer:
When <em>a scientist on Earth drops a hammer and a feather at the same time an astronaut on the moon drops a hammer and a feather, the result</em> expected is that <em>the hammer hits the ground before the feather on Earth, and the hammer and feather hit at the same time on the moon (option D).</em>
Explanation:
In the abscence of atmosphere (vacuum), the objects fall in free fall. This is, the only force acting on the objects is the gravitational pull, which is directed vertlcally downward.
Under such absecence of air, the equations that rules the motion are:
- V = Vo + gt
- d = Vo + gt² / 2
- Vf² = Vo² + 2gd
As you see, all those equations are independent of the mass and shape of the object. This explains why <em>when an astronaut on the moon drops a hammer and a feather at the same time</em>, <em>the hammer and feather hit at the same time on the moon</em>, a space body where the gravitational attraction is so small (approximately 1/6 of the gravitational acceleration on Earth) that does not retain atmosphere.
On the other hand, the air (atmosphere) present in Earth will exert a considerable drag force on the feather (given its shape and small mass), slowing it down, whereas, the effect of the air on the hammer is almost neglectable. In general and as an approximation, the motion of the heavy bodies that fall near the surface is ruled by the free fall equations shown above, so, <em>the result </em>that is<em> expected when a scientist on Earth drops a hammer and a feather at the same time is that the hammer hits the ground before the feather</em>.
Gas particles want to be as free as they can, occupying as much space as they can because they are independent and the greater the temperature the greater their speed, when the temperature is low so is their speed, so they can attach to solvent molecules. When the temperature rises the gas molecules become more agitated and the glue can no longer take them inside the solvent.
Hope this helps!
The coefficients that will balance the tarnishing reaction equation are: 2, 1, 1,1
What is a chemical equation
Chemical equations are representations of chemical reactions using symbols and formula of the reactants and products.
The reactants are located on the left side while the products are located on the right side.
Reactants —> Products
The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.
Thus, we can obtain the coefficients that will balance the tarnishing reaction equation by simply balancing the equation:
How to balance the equation
Ag(s) + H₂S(g) → Ag₂S(s) + H₂(g)
There are 2 atoms of Ag on the right side and 1 atom on the left side. It can be balanced by writing 2 before Ag as shown below:
2Ag(s) + H₂S(g) → Ag₂S(s) + H₂(g)
Thus, the equation is balanced.
The coefficients are: 2, 1, 1, 1 :)
Calcium carbonate contains the carbonate ion. Citric acid is an acid. When an acid reacts with a carbonate, carbon dioxide gas is one of the products. Carbon dioxide gas produces the fizzing effect in water.
Answer:
The molarity of a 50.0 ml aqueous solution containing 10.0 grams of table sal, Nacl, is 3.42
Explanation:
Molarity is a unit of concentration based on the volume of a solution and is defined as the number of moles of solute per liter of solution. Then, the molarity of a solution is calculated by dividing the moles of the solute by the liters of the solution.
Molarity is expressed in units ().
Then you must know the amount of moles of the NaCl solute. For that it is necessary to know the molar mass. Being:
-
Na: 23 g/mole
- Cl: 35.45 g/mole
the molar mass of NaCl is: 23 g/mole + 35.45 g/mole= 58.45 g/mole
Then a rule of three applies as follows: if 58.45 grams are present in 1 mole of NaCl, 10 grams in how many moles will they be?
moles= 0.171
So you know:
- number of moles of solute= 0.171 moles
- volume= 50 mL= 0.05 L
Replacing in the definition of molarity:
Solving:
Molarity= 3.42
<u><em>The molarity of a 50.0 ml aqueous solution containing 10.0 grams of table sal, Nacl, is 3.42 </em></u><u><em></em></u>