What are the following options?
Answer:
For the Extra Credit Question your answer is 6.307e+9
Explanation:
Answer:
A) 6.48 g of OF₂ at the anode.
Explanation:
The gas OF₂ can be obtained through the oxidation of F⁻ (inverse reaction of the reduction presented). The standard potential of the oxidation is the opposite of the standard potential of the reduction.
H₂O(l) + 2 F⁻(aq) → OF₂(g) + 2 H⁺(aq) + 4 e⁻ E° = -2.15 V
Oxidation takes place in the anode.
We can establish the following relations:
- 1 Faraday is the charge corresponding to 1 mole of e⁻.
- 1 mole of OF₂ is produced when 4 moles of e⁻ circulate.
- The molar mass of OF₂ is 54.0 g/mol.
The mass of OF₂ produced when 0.480 F pass through an aqueous KF solution is:

Answer:
The number and the kinds of atoms in the compound
Explanation:
- A chemical formula of a compound contains symbols o the atoms of the elements present in the compound as well as the number of atoms of each element in the form of subscripts.
- Therefore it helps us to know the elements in a compound and the number of atoms in the compounds.