A general formula of an acid always start with an hydronium ion or H+. The general formula of an acid have to end with an anion. As acids, these compounds are named starting with the prefix "hydro-," then adding the first syllable of the anion, then the suffix "-ic."
Answer:
15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution
Explanation:
Step 1: Data given
Nitric acid = HNO3
Molar mass of H = 1.01 g/mol
Molar mass of N = 14.0 g/mol
Molar mass O = 16.0 g/mol
Number of moles nitric acid (HNO3) = 0.25 moles
Molairty = 0.10 M
Step 2: Calculate molar mass of nitric acid
Molar mass HNO3 = Molar mass H + molar mass N + molar mass (3*O)
Molar mass HNO3 = 1.01 + 14.0 + 3*16.0
Molar mass HNO3 = 63.01 g/mol
Step 3: Calculate mass of solute use
Mass HNO3 = moles HNO3 * molar mass HNO3
Mass HNO3 = 0.25 moles * 63.01 g/mol
Mass HNO3 = 15.75 grams
15.75 grams of HNO3 was used and dissolved in 2.5 liters of solvent, to make a 0.10 M solution
Explanation:
To remove the salt from the oil, I will add water to dissolve the salt from it.
Oil is an organic molecule that is non-polar
Salt is polar ionic compound
Salt will not dissolve in the oil.
- Take the mixture.
- Add water to it.
- Water and oil are immiscible
- Shake the new heterogeneous mixture vigorously.
- leave to settle.
- Oil will come on top of the water.
- You can skim off the oil layer on top.
- Then heat the water and salt solution.
- This leaves the oil behind.
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Answer:
The answer to your question is T2 = 610.9 °K
Explanation:
Data
Volume 1 = V1 = 30 cm³
Temperature 1 = T1 = 420 °K
Pressure 1 = P1 = 110 kPa
Volume 2 = V2 = 40 cm³
Temperature 2 = T2 = ?
Pressure 2 = P2 = 120 kPa
Process
To solve this problem use the combined gas law.
P1V1/T1 = P2V2/T2
-Solve for T2
T2 = P2V2T1 / P1V1
-Substitution
T2 = (120 x 40 x 420) / (110 x 30)
-Simplification
T2 = 2016000 / 3300
-Result
T2 = 610.9 °K
