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patriot [66]
4 years ago
8

In an experiment, a ball is drawn from an urn containing 11 orange balls and 8 blue balls. If the ball is orange, three coins ar

e tossed. Otherwise two coins are tossed.
How many elements of the sample space will have a orange ball?
How many elements of the sample space are there altogether?
Mathematics
1 answer:
Sophie [7]4 years ago
4 0

Answer:

a) 4

b) 12

Step-by-step explanation:

Since, when an orange ball is drawn, three coins are tossed. So, sample points are   OHHH, OHHT, OHTH, OHTT. OTHH, 0THT, OTTH, OTTT

So, clearly, 8 sample points will have an orange ball.

When a blue ball is drawn, two coins are tossed. So, sample points are BHH,BHT,BTH,BTT.

So, clearly, 4 samples points will when a blue ball is drawn.

Total samples points=4+8=12

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Answer:

y =  {x}^{2}  - 2

Or if you want with the value of h too.

y =  {(x - 0)}^{2}  - 2

Step-by-step explanation:

y = a {(x - h)}^{2}  + k

Find the value of h and k by using the formula.

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

From y = x²-2

a = 1 \\ b = 0 \\ c =  - 2

Substitute these values in the formula.

h =  -  \frac{0}{2(1)}  \\ h = 0

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Therefore, k = - 2.

From the vertex form, the vertex is at (h, k) = (0,-2). Substitute h = 0, a = 1 and k = -2 in the equation.

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These type of equation where b = 0 can also be both standard and vertex form.

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