If you have anymore questions let me know. I’m sorry if it seems a little bit confusing, just follow the numbers 1,2, and 3.
Given:
Two coins are tossed.
To find:
1. P(H on first coin)?
2. P(H on second coin)?
3. List the paired outcomes for tossing two coins.
4. How many ways are there for two coins to land?
5. What is P(HH)?
Solution:
If a a coin is tossed, then we have to possible outcomes, i.e., heads (H) and tails (T).
It is given that two coins are tossed.
1. The probability of getting a heads on first coin is:

2. The probability of getting a heads on second coin is:

3. If two coins are tossed, then the total possible outcomes are:

4. The number of ways for two coins to land is 4.
5. The probability of the heads on both tosses is:

Therefore, the required solution are:
1. 
2. 
3. List of possible outcomes is
.
4. Number of possible outcomes is 4.
5. 
The percentile score of Jane if she has the highest score of any of the student with a raw score of 87 to take the a standardized math test that includes 100 multiple choice questions, Jane score would be 99.<span><span>Comments </span> <span>Report</span></span>
Answer:
Answer the following question - 10 +(-10)
<h2><u>- 20</u></h2>
-3pa - 9b - 18pc
For starters, you know that you can't take away any of the letters from the equation because none of the three have the exact same letter; however, they all have something they can be divided by and that is -3.
It would be -3 instead of just 3 because the equation itself starts with a negative. (you could probably do it anyways with just 3, but you'd end up taking out a negative one, anyways, so what's the point?)
Now, you would have: -3 ( pa + 3b + 6pc )
That is truly all you can take out. So, that would end up being your answer since all you can really do is simplify.