Hello,
Answer is Dsince y=k(x-2)²-5 and if k=1 ==>D.
Steps:
1. calculate the values of y at x=0,1,2. using y=5-x^2
2. calculate the areas of trapezoids (Bottom+Top)/2*height
3. add the areas.
1.
x=0, y=5-0^2=5
x=1, y=5-1^2=4
x=2, y=5-2^2=1
2.
Area of trapezoid 1 = (5+4)/2*1=4.5
Area of trapezoid 2 = (4+1)/2*1=2.5
Total area of both trapezoids = (4.5+2.5) = 7
Exact area by integration:
integral of (5-x^2)dx from 0 to 2
=[5x-x^3/3] from 0 to 2
=[5(2-0)-(2^3-0^3)/3]
=10-8/3
=22/3
=7 1/3, slight greater than the estimation by trapezoids.
Answer:
The value of the given expression is
Step by step Explanation:
Given that 
To find the value of 
Let us find the value of the expression :
( by using the formula 
here A=2A)
(using 
here A=2A)
(using 
here A=2A)
( using 
here A=2A )
(since tanA=a given )
Therefore
-6 = -3x -12
6 = -3x
x = -2
y = -3(-2) -12
y = 6 -12
y = -6
(-2,-6)
I think :
(-4) + (-4) = -8
or
(-2) + (-2) + (-2) + (-2) = -8
but i am not sure
