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Naily [24]
3 years ago
12

1 point

Mathematics
1 answer:
Delvig [45]3 years ago
3 0

Answer:

Read explanation

Step-by-step explanation:

Wow I'd love to go to that store of yours! :P Anyways if you were asking for the new discounted price I solved this equation: 12*0.8 and got $9.60. But if it was asking for <em>how </em> <em>much </em>was discounted, I would do 12*0.2 and $2.40.

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Q.no 21 solve it. <br> Plz. Plz
tekilochka [14]

Answer:

Hamm i don't know sorry a want yo help You Buy a can't because a don't know sorry

8 0
3 years ago
Which graph has an amplitude of 1/2?
Serjik [45]

Answer:

Step-by-step explanation:

The only graph shown in the question doesn't have amplitude 1/2. look for a graph of a periodic wave function that has maximum y-value 1/2 (0.5) and minimum y-value 1/2 (0.5), or if it is not oscillating around the x-axis, verifies that the distance between minimum y-value and maximum y-value is "1" (one). This is because the amplitude is half of the peak-to-peak distance.

Look at the attached image as example.

8 0
3 years ago
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v&gt;=2i-4tj^
guapka [62]

Given :

A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj  .

To Find :

A. The vector position of the particle at any time t .

B. The acceleration of the particle at any time t .

Solution :

A )

Position of vector v is given by :

d=\int\limits {v} \, dt\\\\d=\int\limits {(2i-4tj)} \, dt \\\\d=(2t)i+\dfrac{4t^2}{2}j\\\\d=(2t)i+(2t^2)j

B )

Acceleration a is given by :

a=\dfrac{dv}{dt}\\\\a=\dfrac{2i-4tj}{dt}\\\\a=\dfrac{2i}{dt}-\dfrac{4tj}{dt}\\\\a=0-4j\\\\a=-4j

Hence , this is the required solution .

5 0
3 years ago
A line passes through the points (2,4) and (5,6) .
Alenkinab [10]

Answer:

Option B and D are correct.

Step-by-step explanation:

Given: A line passes through the points (2,4) and (5,6).

* Case 1:

If a line passes through the points (2, 4) and (5, 6)

Point slope intercept form:

for any two points (x_1,y_1) and (x_2, y_2)

then the general form y -y_1=m(x-x_1) for linear equations where m is the slope given by:

m =\frac{y_2-y_1}{x_2-x_1}

First calculate slope for the points (2, 4) and (5, 6);

m = \frac{y_2-y_1}{x_2-x_1} =\frac{6-4}{5-2} = \frac{2}{3}

then, by point slope intercept form;

y-4=\frac{2}{3}(x-2)

* Case 2:

If a line passes through the points (5, 6) and (2, 4)

First calculate slope for the points (5, 6) and (2, 4);

m = \frac{y_2-y_1}{x_2-x_1} =\frac{4-6}{2-5} = \frac{-2}{-3}= \frac{2}{3}

then, by point slope intercept form;

y-6=\frac{2}{3}(x-5)

Yes, the only equation of line from the given options  which describes the given line are;

y-4=\frac{2}{3}(x-2)  and y-6=\frac{2}{3}(x-5)



8 0
4 years ago
Which equation would find the distance between the
Andreyy89

Step-by-step explanation:the answer is c i promise

3 0
3 years ago
Read 2 more answers
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