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adoni [48]
3 years ago
15

How do i add a mixed fraction with different denominators

Mathematics
2 answers:
salantis [7]3 years ago
7 0

Step 1: Find the Lowest Common Multiple (LCM) between the denominators.

Step 2: Multiply the numerator and denominator of each fraction by a number so that they have the LCM as their new denominator.

Step 3: Add or subtract the numerators and keep the denominator the same.  

Step 4: If the answer is an improper form, reduce the fraction into a mixed number.

I hope this helped!

Yamauchi Wang


Marina86 [1]3 years ago
6 0

Answer:

give me the sum and i will show step by step explanation

Step-by-step explanation:


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Help i will give an award!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
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Answer: Plug in answers work backwards; or learn log to get rid of powers

Step-by-step explanation: save time on your test by cheating yourself of knowledge

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3 years ago
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I’m really struggling on this <br> It’s a puzzle and I can’t do it i don’t know what to do
WINSTONCH [101]

Answer:

Maby you add up the sides and put it in?

Step-by-step explanation:

5 0
3 years ago
9)Solve e/4 – 10 = -20 (CHECK on your graph paper.)
rusak2 [61]

Answer:

9) e=-40 10) k=9

Step-by-step explanation:

9) e/4-10=-20  add 10 on both sides

e/4=-10  Multiply everything by 4

e=-40

10) 0.4k-4+1.6k=14   combine like terms

2k-4=14   Add 4 on both sides

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5 0
3 years ago
A football stadium sells regular and box seating. There are twelve times as many
Vera_Pavlovna [14]

Answer:

There are 801 box seats and 9612 regular seats.

explanation:

Let the number of box seats be x,

Then the regular seats is 12x

The sum of seats equals to 10,413

<u>Solve:</u>

12x + x ➙ 10,413

13x ➙ 10413

x ➙ 801

There are 801 box seats.

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➙ 12(x)

➙ 12(801)

➙ 9612

There are 9612 regular seats.

6 0
2 years ago
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One of two small classrooms is chosen at random with equally likely probability, and then a student is chosen at random from the
bixtya [17]

Answer:

0.1875

Step-by-step explanation:

Let A be the event that  class two has been chosen . So the probability of A would be P (A) = 1/2= 0.5

Now class two has 9 girls out of total 24 students . So the probability of chosing the girl would be= P (B=) 9/24= 0.375

So the probability that Classroom #2 was chosen at random, given that a girl was chosen is given by = P(A) . P(B)= 0.5 * 0.375= 0.1875

Another way of finding the probability that Classroom #2 was chosen at random, given that a girl was chosen is by drawing a tree diagram.

P (1/2) Class 1 ------------------------5 boys

                      -------------------------11 girls  (11/16)

P (1/2)  Class 2 -------------------------15 boys

                     -----------------------9 girls  P (9/24)   Class 2 was chosen (0.5) *9/24

8 0
3 years ago
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