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lara [203]
3 years ago
9

One of two small classrooms is chosen at random with equally likely probability, and then a student is chosen at random from the

chosen classroom. Classroom #1 has 5 boys and 11 girls. Classroom #2 has 15 boys and 9 girls. What is the probability that Classroom #2 was chosen at random, given that a girl was chosen? Your answers should be rounded to 4 digits after the decimal.
Mathematics
1 answer:
bixtya [17]3 years ago
8 0

Answer:

0.1875

Step-by-step explanation:

Let A be the event that  class two has been chosen . So the probability of A would be P (A) = 1/2= 0.5

Now class two has 9 girls out of total 24 students . So the probability of chosing the girl would be= P (B=) 9/24= 0.375

So the probability that Classroom #2 was chosen at random, given that a girl was chosen is given by = P(A) . P(B)= 0.5 * 0.375= 0.1875

Another way of finding the probability that Classroom #2 was chosen at random, given that a girl was chosen is by drawing a tree diagram.

P (1/2) Class 1 ------------------------5 boys

                      -------------------------11 girls  (11/16)

P (1/2)  Class 2 -------------------------15 boys

                     -----------------------9 girls  P (9/24)   Class 2 was chosen (0.5) *9/24

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The lifetime of LCD TV sets follows an exponential distribution with a mean of 100,000 hours. Compute the probability a televisi
kondaur [170]

Answer:

0.9

0.3012

0.1809

230258.5

Step-by-step explanation:

Given that:

μ = 100,000

λ = 1/μ = 1 / 100000 = 0.00001

a. Fails in less than 10,000 hours.

P(X < 10,000) = 1 - e^-λx

x = 10,000

P(X < 10,000) = 1 - e^-(0.00001 * 10000)

= 1 - e^-0.1

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b. Lasts more than 120,000 hours.

X more than 120000

P(X > 120,000) = e^-λx

P(X > 120,000) = e^-(0.00001 * 120000)

P(X > 120,000) = e^-1.2

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c. Fails between 60,000 and 100,000 hours of use.

P(X < 60000) = 1 - e^-λx

x = 60000

P(X < 60,000) = 1 - e^-(0.00001 * 60000)

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Take the In

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3 0
3 years ago
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Answer:

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