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3 years ago

Which statement about the data is true?

Mathematics

2 answers:

ss7ja [257]3 years ago

7 0

I think it's B, there no repeating number.

lana [24]3 years ago

6 0

Answer:

The median is the only appropriate measure of center.

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If f(x)=-4x+1 what is f(-x/2)

guapka [62]

Answer:

f( $\frac{-x}{2}$ )=2x+1

Step-by-step explanation:

given f(x)=-4x+1................(1)

x= $\frac{-x}{2}$ put in equ (1)

f(x)=-4x+1

f( $\frac{-x}{2}$ ) =-4( $\frac{-x}{2}$ )+1

f( $\frac{-x}{2}$ )=2x+1 answer

5 0

3 years ago

Given that the measurement is in centimeters, find the area of the circle to the nearest tenth.(Use 3.14 for n) Radius is 3

olasank [31]

List the a b c d platform if you have it

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3 years ago

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Inver laplace <img src="https://tex.z-dn.net/?f=%20%7Bl%7D%5E%7B%20-%201%7D%20%28%20%20%5Cfrac%7Bs%7D%7B%28%20%20%7Bs%7D

kipiarov [429]

Answer:

_______________

ls^4 + 32ls^2 + 256l

Step-by-step explanation:

I used an algebra calculator called MathPapa to solve your equation.

Also, welcome to brainly!

7 0

2 years ago

"explain how you know" and i will give brainliest:)

larisa [96]

Answer:

Step-by-step explanation:

first one is 9,14 the second one is 1,3 and the last one is 1, -3

5 0

3 years ago

Find cos(2*ABC) 100POINTS

juin [17]

Answer:

$-\dfrac{7}{25}$

Step-by-step explanation:

Trigonometric Identities

$\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B$

Trigonometric ratios

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

$\cos(\angle ABC)=\dfrac{3}{5}$

$\sin(\angle ABC)=\dfrac{4}{5}$

Therefore, using the trig identities and ratios:

$\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}$

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2 years ago

Read 2 more answers