Check the picture below.
so the area of the hexagon is really just the area of two isosceles trapezoids.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=2 \end{cases}\implies \begin{array}{llll} A=\cfrac{2(2+4)}{2}\implies A=6 \\\\\\ \stackrel{\textit{twice that much}}{2A = 12} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2%5C%5C%20b%3D4%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B2%282%2B4%29%7D%7B2%7D%5Cimplies%20A%3D6%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%20%3D%2012%7D%20%5Cend%7Barray%7D)
Divide the numerical coefficients and write the quotation in simplest form
B they only have one pair of parallel sides. The top and bottom
Answer:
adult tickets = 17, children tickets = 9
Step-by-step explanation:
Let x be the number of children and y the number of adults
Then given that 26 tickets are sold, we can write
x + y = 26 → (1)
Given that ticket cost was $194 we can write
5.5x + 8.5y = 194 → (2)
Rearrange (1) expressing y in terms of x by subtracting x from both sides
y = 26 - x → (3)
Substitute y = 26 - x into (2)
5.5x + 8.5(26 - x) = 194 ← distribute and simplify left side
5.5x + 221 - 8.5x = 194
- 3x + 221 = 194 ( subtract 221 from both sides )
- 3x = - 27 ( divide both sides by - 3 )
x = 9
Substitute x = 9 into (3) for corresponding value of y
y = 26 - 9 = 17
Hence number of adult tickets sold = 17
number of children tickets sold = 9
Answer:
864 cm
Step-by-step explanation: