-2 = - x + x^2 -4 => x^2 - x - 4 + 2 = 0
x^2 - x - 2 = 0
a is the coefficient of x^2 => a = 1
b is the coefficient of x => b = - 1
c is the constant term => c = - 2
quadratic equation: [- b +/- √(b^2 - 4ac) ] / 2a =
= { 1 +/- √[ (-1)^2 - 4(1)(-2)] } / (2(1) = { 1 +/- √ (1 + 8) } / 2 = {1 +/- √9} / 2 =
= { 1 +/- 3} / 2
9514 1404 393
Answer:
B. 1/((x -1)(x -2))
Step-by-step explanation:
The vertical asymptotes at x=1 and x=2 tell you the denominator will have factors such that these values make it zero: (x -1)(x -2). That is sufficient to identify choice B as the correct answer.
Answer:
X=19/32
Step-by-step explanation:
3/4^2+1^2=2*x
3/4^2+1=2x
3+(4^2)/4^2=2x
3+16/4^2=2x
19/4^2=2x
19/(2^2)^2=2x
19=16(2x)
19=16*2x
32x=19
32x/32=19/32
x=19/32
This took alot of time goodluck!
Step-by-step explanation:
Find the Center and Radius (x-4)^2+y^2=4
(
x
−
4
)
2
+
y
2
=
4
This is the form of a circle. Use this form to determine the center and radius of the circle.
(
x
−
h
)
2
+
(
y
−
k
)
2
=
r
2
Match the values in this circle to those of the standard form. The variable
r
represents the radius of the circle,
h
represents the x-offset from the origin, and
k
represents the y-offset from origin.
r
=
2
h
=
4
k
=
0
The center of the circle is found at
(
h
,
k
)
.
Center:
(
4
