6^5 = 6•6•6•6•6
x^7 = x•x•x•x•x•x•x
x^5 = x•x•x•x•x
5^6 = 5•5•5•5•5•5
Answer:
The constant force exerted on the ball by the wall is 119.68 N.
Step-by-step explanation:
Consider the provided information.
It is given that the mass of the ball is m = 2.2 kg
The initial velocity of the ball towards left is 7.4 m/s
So the momentum of the ball when it strikes is =
The final velocity of the ball is -6.2 m/s
So the momentum of the ball when it strikes back is =
Thus change in moment is:
The duration of force exerted on the ball t = 0.25 s
Therefore, the constant force exerted on the ball by the wall is:
Hence, the constant force exerted on the ball by the wall is 119.68 N.
Solutions
<span>To solve the problem our first step is to find the prime factorization of each number. </span>
4 = 2²
<span>5 = 5 </span>
<span>6 = 2 x 3
</span>
Calculations
<span>LCM = 2² x 3 x 5 = 60 </span>