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Olegator [25]
4 years ago
11

Identify the quadratic term in the function, f(x)=2x^2-3x+5

Mathematics
1 answer:
Nadusha1986 [10]4 years ago
7 0
Answer: 2x^2

The three terms are
2x^2
-3x
5
as they are separated by a plus sign. You can think of it as 2x^2 + (-3x) + 5 if you want. The quadratic term is the term with the exponent of 2
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What are the roots of the polynomial equation? (picture below)
Marat540 [252]

Answer:

x = - 9, x = 0, x = 7

Step-by-step explanation:

Given

\frac{1}{2} x(x - 7)(x + 9) = 0 ← in standard form

Equate each factor to zero and solve for x

\frac{1}{2} x = 0 ⇒ x = 0

x - 7 = 0 ⇒ x = 7

x + 9 = 0 ⇒ x = - 9

3 0
3 years ago
Read 2 more answers
What percent of 8 is 20
gavmur [86]
You write it as a improper fraction first*
 20
-----
  8
and then u divide 8 into 20 
and we know that it goes in it 2.5 times
so simply from here
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3 0
3 years ago
Multiply & simplify: (2a - 3)(2a + 1)
RoseWind [281]
I hope this helps you



2a.2a+1.2a-3.2a-3.1


4a^2+2a-6a-3


4a^2-4a-3
3 0
3 years ago
A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The
Readme [11.4K]

Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

3 0
4 years ago
Toronto FC have lost 25% of their games if they have played 16 games how many would they have lost
bija089 [108]

Answer:

4

Step-by-step explanation:

4 0
3 years ago
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