Answer:
<em>(1, - 2) </em>
Step-by-step explanation:
2x - y = 4
3x + y = 1
A = ![\left[\begin{array}{cc}2&-1\\3&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-1%5C%5C3%261%5Cend%7Barray%7D%5Cright%5D)
= 2(1) - 3( - 1) =2 + 3 = 5
= ![\left[\begin{array}{cc}4&-1\\1&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%26-1%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D)
= 4(1) - 1(- 1) = 4 + 1 = 5
= ![\left[\begin{array}{cc}2&4\\3&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%264%5C%5C3%261%5Cend%7Barray%7D%5Cright%5D)
= 2(1) - 4(3) = 2 - 12 = - 10
<em>x </em>= 
=<em> 1</em>
<em>y </em>= 
= <em>- 2</em>
<em>(1, - 2)</em>
14/99
Select 1 marble; the chance that it is white is 4/12. Select a 2nd marble; the chance that it is white is 3/11. Select a 3rd; the chance it is white is 2/10. Select a 4th; the chance it is red is 8/9. Select a 5th; the chance it is red is 7/8. The chance of getting this specific set of 5 marbles in this order is (4/12)×(3/11)×(2/10)×(8/9)×(7/8)=(2×7)/(11×10×9).
This specific set could occur in the permutation of 5 things taken 5 at a time where 3 are identical (white), and the other 2 are also identical (red). The formula for this is 5!/(3!2!)=10.
Combining the chance of getting white, white, white, red, red with the number of ways 3 white and 2 red could have been distributed in the draw of 5 marbles gives the answer:
{(2×7)/(11×10×9)}×10=14/99
A similar process will show that the chance of getting 5 red marbles is 7/99; 4 white and 1 red is 1/99; 2 white and 3 red is 42/99; and 1 white and 4 red is 35/99.
395 *25% could also be interpreted as 395/4
395 = 98.75
4
Well how long is the ribbon? I'm not asking for the dollar amount, I will answer your question if you can tell me the length of the ribbon. No one can figure it out unless you give the total length.
